Solved

Button that doesn't post back, but has onchange javascript function

Posted on 2004-08-19
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Last Modified: 2008-01-09
I want to have a button that looks like a button, but doesn't post back to the server... so I guess I couldn't really call it a button. I have a button control with

      addTransBTN.Attributes.Add("onclick","openNewWin();");

but it still posts back to the server when clicked, causing my page to reload. Do I use a different control, or how does one normally work around this?
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Question by:RichardFox
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7 Comments
 
LVL 3

Assisted Solution

by:gspronych
gspronych earned 125 total points
ID: 11846795
If you want a button that doesn't do a server postback, you want a input box.
<INPUT type="button" value="Button">

Or click the toolbox, select HTML, and drag the button on the form.

The HTML button does not perform a server side postback
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Author Comment

by:RichardFox
ID: 11847014
ok, but how do I work with this in a codebehind file?
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LVL 18

Accepted Solution

by:
DotNetLover_Baan earned 125 total points
ID: 11847015
Hi there ..
get an HTML button as gspronych said. Right click on it. Make it "Run at server". Assign a name to it using Property box. Say "Button1". In the page load add the attribute...

        Button1.Attributes.Add("OnClick", "javascript:openNewWin();")

-Baan
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LVL 3

Expert Comment

by:gspronych
ID: 11852853
If you want it to run codebehind richardfox it needs to be a server control as Baan said.
BUT a server control will cause a postback.

If the name of the control is Button1, put this code in your page_load
        Button1.AutoPostBack = False


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LVL 18

Expert Comment

by:DotNetLover_Baan
ID: 11853503
No.. gspronych  , if it is an HTML control.. it won't.
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Author Comment

by:RichardFox
ID: 11870451
I need to create these controls dynamically. I understand the suggestion, but I need to add the HTML button when I create the rest of my controls, so I can't drag it from the toolbox and right click it and specify "Run at server". How can I do this from code?
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Author Comment

by:RichardFox
ID: 11872583
I created a dynamic control

HtmlControls mybutton;

and set the onclick function, works great, thanks!
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