how do you take a char out of a string

Hi again Pern

you could use code similar to this

str_Test = "@hello"

str_Test =replace(str_Test,"@","")

HTH

Scott

NewString = Replace("@hello", "@", "")

Colosseo types faster!

and if @hello is in a string of other words...

str_Test = "other words @hello around hello"

str_Test =replace(str_Test,"@hello","hello")

Scott

- BlueDevilFan -- Colosseo has nothing better to do :)

wlist.text="@hello"

WList.Text = Mid(WList.Text, 2)

i get a blank WList.Text when i try to do this anyhelp?

Hi pern what kind of object is wlist?

a listbox

hahaha that did it i just didnt make it save itsself

NewString= Mid(WList.Text, 2)

and that works perfectly

thanks alot heres your points again

side note is there a way to update the listbox esaly with out repopulating it with the take out @?

Hi pern glad its working :)

You could try code like this to loop through all items in the listbox

if the item starts with an @ then the @ is stripped off

For i = 0 To WList.ListCount - 1
  If Left(WList.List(i), 1) = "@" Then WList.List(i) = Mid(WList.List(i), 2)
Next

Hope that works for you mate

Thanks for the grade

Scott

it would have to match the one we striped and leave the rest as is

well using the code above

@hello
hello
test
@test

would return

hello
hello
test
test

but it could be changed to only affect @hello

so for it to return

hello
hello
test
@test

For i = 0 To WList.ListCount - 1
  If WList.List(i) = "@hello" Then WList.List(i) = Mid(WList.List(i), 2)
Next

Hope thats what you meant

Cheers

Scott

thats right listboxes are sorta like arrays im stupid i should known that..guess im code burnt...rain always makes me tired and its pouring here

i also made the code change just the var i wanted and sent it via the newstring worked great

yes thats what i wanted thanks alot