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String variable formats

In the following lines of code:

m_strFreeMemory.Format("%ld KB");
m_strMemoryLoad.Format("%d %%");

What does %d, %%, %ld do exactly?
0
fattumsdad
Asked:
fattumsdad
1 Solution
 
Nass89Commented:
Hi,
The correct codes are:
m_strFreeMemory.Format("%ld KB", a);
m_strMemoryLoad.Format("%d",a);
it must contain an arguemnt for every '%' you use.

"%ld KB", is the format specifier and a is the arguement. The first part specifies which format to use to store the arguement in string.
example:
int a=255;
m_strFreeMemory.Format("%d ", a); --------> Display: 255
m_strFreeMemory.Format("%x ", a); --------> Display: 0xff
m_strFreeMemory.Format("%X ", a); --------> Display: 0xFF


A format specification has the following form:

%[-][#][0][width][.precision]type

See 'wsprintf' in MSDN for more info.

Good Luck!
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