Parse error

I am trying to store 5 sports names in a sequence but I am getting a parse error on the "for" line? I can not figure it out? Thanks

#include <stdio.h>
#include<string.h>
int main()

{
   char sports [5][15];
   
    strcpy(sports[0],"tennis");
    strcpy(sports[1],"football");
    strcpy(sports[2],"basketball");
    strcpy(sports[3],"baseball");
    strcpy(sports[4],"gymnastics");
 
     for(int i=0; i<5; i++)
{        
printf("%s\n",sports[i]);
printf("%s\n",sports[i]);
printf("%s\n",sports[i]);
printf("%s\n",sports[i]);
printf("%s\n",sports[i]);
printf("exiting...\n");  

}
getch();
return 0;                          
}          
RebeccaFuscoAsked:
Who is Participating?
 
Jaime OlivaresConnect With a Mentor Software ArchitectCommented:
You must use:
    for(i=0;i<5;i++)  

Altough you have declared i above, still you must initialize it
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Jaime OlivaresConnect With a Mentor Software ArchitectCommented:
Are you using a C compiler instead of C++ compiler?
Declare "int i" just below char sports[5][15];
and use it inside the "for" without declaring:
for (i=0; .... etcetera)
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kumvjuecCommented:
hi!!

Isn't your question answered elsewhere :). Why don't you just delete it and reclaim your points
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RebeccaFuscoAuthor Commented:
Still not right? It is the "for" thing again.

#include <stdio.h>
#include<string.h>
int main()

{
   char sports [5][15];
   int i;
    strcpy(sports[0],"tennis");
    strcpy(sports[1],"football");
    strcpy(sports[2],"basketball");
    strcpy(sports[3],"baseball");
    strcpy(sports[4],"gymnastics");
 
    for(i<5;i++)  
       
printf("%s\n",sports[i]);
printf("exiting...\n");  
}
}
getch();
return 0;                          
}          

0
 
kumvjuecConnect With a Mentor Commented:
hi rebecca :)
see, the for statement has three parts, separated by semicolons. the first part is where you initialize, 2nd is where you check the condition and 3rd where you make some change to the variables. Since your code above doesn't have two semicolons, it will give error.
Refer to my last comment in your earlier question
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kumvjuecCommented:
thanks for the points though ;-)
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RebeccaFuscoAuthor Commented:
Thanks for your help I really appreciate it. Give me a year of this web-site and C programming and I will know what I am doing ;-)  
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RebeccaFuscoAuthor Commented:
I fixed the final parse error I was gettting and it does compile but still does not display the names in a sequence? Does that mean the "for" loop is not working?

 #include <stdio.h>
#include<string.h>
int main()

{
   char sports [5][15];
   int i;
    strcpy(sports[0],"tennis");
    strcpy(sports[1],"football");
    strcpy(sports[2],"basketball");
    strcpy(sports[3],"baseball");
    strcpy(sports[4],"gymnastics");
 
    for(i=0;i<5;i++)  /*use a \0*somewhere? */
       
printf("%s\n",sports[i]);
printf("exiting...\n");  

getch();
return 0;                          
}          

0
 
kumvjuecCommented:
what are you meaning by sequence?? is it not printing anything??
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RebeccaFuscoAuthor Commented:
It is just printing out the five different sports and I was trying to get it to print out like 2 rows of the five across and 10 of the 5 sports down like a continous or connected series.
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kumvjuecCommented:
try removing "\n" from the
printf("%s\n",sports[i]);

btw, if that is still not what you want, type here how you want it to be.
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RebeccaFuscoAuthor Commented:
example

1234512345
1234512345
1234512345
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Jaime OlivaresSoftware ArchitectCommented:
Alternatively, you can declare your array as follow:

char *sports[] = { "tennis", "football", "basketball", "baseball", "gymnastics" };
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RebeccaFuscoAuthor Commented:
Thanks that works. How do I get it to go down 5 rows?   I though the array would do that?        
#include <stdio.h>
#include<string.h>
int main()

{
   char *sports[]={"tennis","football","basketball","baseball","gymnastic"};
   int i;
    strcpy(sports[0],"tennis");
    strcpy(sports[1],"football");
    strcpy(sports[2],"basketball");
    strcpy(sports[3],"baseball");
    strcpy(sports[4],"gymnastics");
 
    for(i=0;i<5;i++)  /*use a \0*somewhere? */
       
printf("%s",sports[i]);
getch();
return 0;                          
}          


0
 
Jaime OlivaresSoftware ArchitectCommented:
No, don't need to use strcpy:

Thanks that works. How do I get it to go down 5 rows?   I though the array would do that?        
#include <stdio.h>
#include<string.h>
int main()

{
   char *sports[]={"tennis","football","basketball","baseball","gymnastic"};
   int i;
 
    for(i=0;i<5;i++)  /*use a \0*somewhere? */
        printf("%s",sports[i]);

    getch();
    return 0;                          
}          

0
 
Jaime OlivaresSoftware ArchitectCommented:
Not sure about your requirement

#include <stdio.h>
int main()
{
   char *sports[]={"tennis","football","basketball","baseball","gymnastic"};
   int i, j;
 
    for(i=0;i<5;i++)
        for (j=0; j<10; j++)
             printf("%s",sports[j%5]);

    getch();
    return 0;                          
}          

0
 
RebeccaFuscoAuthor Commented:
That is more what I was trying to do. So I just have to add in the other "for" loop to run them in row and columns? I have been wanting to play around with the \0 function so I am going to try that next. Thank you both for your help today.  Rebecca
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Jaime OlivaresSoftware ArchitectCommented:
if you want to put a space between words, use

printf("%s  ", ..... etcetera

to jump at the end of each line use

printf ("\n\r");

Here is the resume:

#include <stdio.h>
int main()
{
   char *sports[]={"tennis","football","basketball","baseball","gymnastic"};
   int i, j;
 
    for(i=0;i<5;i++) {  // 5 rows
        for (j=0; j<10; j++)   // 10 elements per line
             printf("%s  ",sports[j%5]);
        printf ("\n\r");    // this line is outside the for(j... loop
    }

    getch();
    return 0;                          
}      
0
 
RebeccaFuscoAuthor Commented:
cool thanks :-) I did not know about the jump at the end of each line.  
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