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Converting a String arry of CAPS to Init Caps

Posted on 2004-08-23
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Last Modified: 2011-09-20
hi Experts,
                What is the most efficient way to convert a string Array of all CAPS to init Caps..That is the first letter of each word {greater than 3 Characters ..} is capitalised  But the starting alphabet of the stirng is always capitalixed.. irrepective of whether it is 3 characters long or not.... For example..

1) I AM THE STRING WHICH IS TO BE CAPITALIZED..

should be converted into

Output : I am the String Which is to be Capitalized.

What is the most efficient way to do this..

Pls give me the most efficient way to approach this .

Thanx in Advance.

Regards,
newBie Programmer
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Question by:FearFactor_x
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4 Comments
 
LVL 35

Expert Comment

by:TimYates
ID: 11871231
String tgt="THIS IS A TEST";
StringBuffer s=new StringBuffer(tgt.toLowerCase());
boolean raise=true;
for(int i=0; i<s.length(); ++i)
{   if(raise && !Character.isSpace(s.charAt(i)))
    {   s.setCharAt(i,Character.toUpperCase(s.charAt(i)));
        raise=false;
    }
    else if(!raise && Character.isSpace(s.charAt(i)))
    {   raise=true;
    }
}
String ns=new String(s);
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LVL 35

Expert Comment

by:TimYates
ID: 11871238
That was from http://www.experts-exchange.com/Programming/Programming_Languages/Java/Q_10235434.html

There is also a class in the Apache Commons libraries to do this...  TextUtils class I think (but I can't be 100% sure)
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LVL 18

Accepted Solution

by:
bobbit31 earned 50 total points
ID: 11871319
and if you want it to do it so that it doesn't capitalize words 3 chars and under:

String tgt = "THIS IS A TEST";
StringTokenizer st = new StringTokenizer(tgt, " ");

String tmp;
String ret = "";
while (st.hasMoreTokens()) {
   tmp = st.nextToken();
   if (tmp.length() > 3) {
     ret += Character.toUpperCase(tmp.charAt(0)) + tmp.substring(1).toLowerCase() + " ";
   } else {
     ret += tmp.toLowerCase() + " ";
   }
}
System.out.println(tmp);
0
 
LVL 18

Expert Comment

by:bobbit31
ID: 11871337
oops:

System.out.println(ret);
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