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How Do I Start A Program With A Particular File

Posted on 2004-08-24
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Last Modified: 2010-04-23
Hi,

I am trying to start a program C:FlashPla.exe and have it open a particular file when it appears.

How do I do this?

B-
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Question by:bczingo
6 Comments
 
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Expert Comment

by:DotNetLover_Baan
ID: 11882578
use...
Process.Start("File Address")
-Baan
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DotNetLover_Baan earned 500 total points
ID: 11882619
for example..   Process.Start("IExplore.exe", "C:\myPath\myFile.htm")
http://msdn.microsoft.com/library/en-us/cpref/html/frlrfSystemDiagnosticsProcessClassStartTopic.asp
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Expert Comment

by:Desp
ID: 11882655
System.Diagnostics.Process.Start("Your_File_path")
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LVL 19

Expert Comment

by:Desp
ID: 11882678
path of the particular file that you want to open with FlashPla.exe
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Expert Comment

by:imu79
ID: 11882735
something like this:

dim oStartInfo as New System.Diagnostics.ProcessStartInfo
with oStartInfo
   .FileName = "C:\FlashPlay.exe"
   .Arguments = "C:\myFlash.swf"
   .WindowStyle = ProcessWindowStyle.Normal
end with

System.Diagnostics.Process.Start(oStartInfo)

Look at the ProcessStartInfo class for more options to customize the way you start the new process. Both the Process and the ProcessStartInfo classes are in the System.Diagnostics namespace.

hope this helps..
Imran.
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Expert Comment

by:RonaldBiemans
ID: 11882871
or

Shell("c:\FlashPla.exe " & yourfile, AppWinStyle.MaximizedFocus)
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