Exchanger 2K

Hello,
 
I have Win2k network with Exchange 2K.  I am doing some testings with the mailing list and I have this question.
 
Is there a way to stop the exit of emails from the Exchange 2k server and be able to identify all of them?
 
Thank you very much for your help.
batdacchiAsked:
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rhandelsConnect With a Mentor Commented:
Hi,

Don't really know why you would like to do this, but he, your question (do make sure not to brake privacy policies).

Make sure to stop Exchange's SMTP engine, after that, go to the Exchange install path and then gop to the mailroot\vsi\queue folder. All mails are queued in this folder before being send.

Maybe the mails are not set in the queue folder, because the SMTP engine is stopped, if so, then make sure that you add a non existing Smart Host, this way the SMTP engine will try to keep on sending the mail and it stays in the queue..
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mikeleebrlaCommented:
there are plenty of third party tools that do this,,, a google search will lead your twards some,, but this cannot be done without third party tools to my knowledge.   Asking this question in the exchange email forum might give you better results.
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jdeclueConnect With a Mentor Commented:
From within the Exchange System Administrator, you can open up the Administrative Groups | Group | Servers | Server Name | Protocols | SMTP | SMTP (or Default) | Queues

Under Queues you will find local delivery (your domain) and all others. You can right click on any queue and select "FREEZE", after you select Freeze you right click again and select "Enumerate 100 Messages". You can keep clicking on Enumerate 100 Message to Refresh the email displayed on the Right hand window pane. When you are done looking at the messages remember to Right Click on the Queue and select "UNFREEZE" to start the mail flow again.

Using FREEZE, Enumerate and UNFREEZE, you can send mail into the queue and watch it build up, review the information and then let the mail go.

J
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rhandelsCommented:
Points split between me and jdeclue. We both gave good answers..
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jdeclueCommented:
Absolutely, rhandels answer will do the trick, and my answer is correct... without a doubt.

J
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