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simple syntax question

Hi,

Is there anything wrong with the following in Perl:

if(0){;}
elsif(($char eq "'") or ($char == '"')){;}

Perl does not seem to like '"', but I think it is valid.
0
rmundkowsky
Asked:
rmundkowsky
1 Solution
 
kanduraCommented:
You're right:

    c:\> perl -c
    if(0){;}
    elsif(($char eq "'") or ($char == '"')){;}
   
    - syntax OK

Maybe the error occurs further up your script?
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rmundkowskyAuthor Commented:
Ah, yep you got it.  Thanks
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ozoCommented:
perl -Mdiagnostics -w
if(0){;}
elsif(($char eq "'") or ($char == '"')){;}

Use of uninitialized value in string eq at - line 1 (#1)
    (W uninitialized) An undefined value was used as if it were already
    defined.  It was interpreted as a "" or a 0, but maybe it was a mistake.
    To suppress this warning assign a defined value to your variables.
   
    To help you figure out what was undefined, perl tells you what operation
    you used the undefined value in.  Note, however, that perl optimizes your
    program and the operation displayed in the warning may not necessarily
    appear literally in your program.  For example, "that $foo" is
    usually optimized into "that " . $foo, and the warning will refer to
    the concatenation (.) operator, even though there is no . in your
    program.
   
Argument """ isn't numeric in numeric eq (==) at - line 1 (#2)
    (W numeric) The indicated string was fed as an argument to an operator
    that expected a numeric value instead.  If you're fortunate the message
    will identify which operator was so unfortunate.
   
Use of uninitialized value in numeric eq (==) at - line 1 (#1)
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