help with String tokenizer

Posted on 2004-08-25
Last Modified: 2010-03-31
i have a string

 2d 1 3d 1 animation 1 curve 1 graphic 1

and i want to break them into tokens and leaving out the numbers i know you could do this by

StringTokenizer token = new StringTokenizer(string,"1234567890");

but that removes the 2 in 2d which i want to keep intact can anyone help
Question by:rimmer007
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LVL 92

Expert Comment

ID: 11898352
Try a StreamTokenizer instead.
LVL 92

Expert Comment

ID: 11898355
LVL 92

Expert Comment

ID: 11898359
If you need to use a StringTokenizer then use:
StringTokenizer token = new StringTokenizer(string);

and then use Integer.parseInt() to check if each token is a number or not.
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LVL 18

Accepted Solution

armoghan earned 63 total points
ID: 11899232
String a = "2d 1 3d 1 animation 1 curve 1 graphic 1";
    StringTokenizer token = new StringTokenizer(a);
          int i = Integer.parseInt(token.nextToken());
        }catch (Exception e)

Expert Comment

ID: 11902920
Just to confirm, does the string have space between the two words/characters, i.e "2d 1 3d 1".

If yes, we can use the space " " as a delimiter?
just a basic workaround

String l_Str = "2d 1 3d 1 animation 1 curve 1 graphic 1";

StringTokenizer l_Tok = new StringTokenizer(l_Str, " ");
while (l_Tok.hasMoreElements()) {
      String l_Elem = (String)l_Tok.nextElement();

      if(l_Elem.length()>1) {

Author Comment

ID: 11923848

i using armoghan method and i m trying to print out the strings

i put this

  System.out.println("String  " + Integer.toString(i));

inside the catch but numbers are printed what am i doin wrong?
LVL 92

Assisted Solution

objects earned 62 total points
ID: 11923961
you can't print out the value using that code, instead try:

String s = "2d 1 3d 1 animation 1 curve 1 graphic 1";
StringTokenizer i = new StringTokenizer(s);
while (i.hasMoreTokens())
          String token = i.nextToken();
          int n = Integer.parseInt(token);
    catch (Exception e)
        System.out.println("String  " + token);

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