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When can I delete the physical file when using javax.mail MimeBodyPart

Hi!
I'm using the MimeBodyPart to add files as attachments.
The point is that I want to delete the files before sending the message.
Can you let me know if and when I can delete it?
The code that I'm talking about (from the javax.mail example) is:

Multipart multipart = new MimeMultipart();
multipart.addBodyPart(messageBodyPart);

// Part two is attachment
messageBodyPart = new MimeBodyPart();
DataSource source = new FileDataSource(filename);
messageBodyPart.setDataHandler(new DataHandler(source));
messageBodyPart.setFileName(filename);
multipart.addBodyPart(messageBodyPart);

Thanks!

Mick Barry

after you have sent it I'd say.

rzvika2

ASKER

No, I need a way to delete it before sending.

Mick Barry

Then read it into memory, and use a memory based DataSource.

rzvika2

ASKER

Can you give me an example please?

Mick Barry

http://ws.apache.org/soap/docs/apiDocs/org/apache/soap/util/mime/ByteArrayDataSource.html

TimYates

there's an example of ByteArrayDataSource in the examples that come with javamail...

rzvika2

ASKER

Thanks, I have another related issue,
I need to convert my Multipart to a byte array and the easiest thing is using serialization.
I can't do it because the Multipart is not serializable.
What is your best solution?
Thanks!

ASKER CERTIFIED SOLUTION

Mick Barry

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rzvika2

ASKER

I have class A that has String, and I have class B that extends A and has Integer and Multipart.
I need 2 methods in class B, one to load the object according to byte[] and one to save to byte[].
The easiest way was to do:
on save:
      ByteArrayOutputStream bos = new ByteArrayOutputStream();
      ObjectOutputStream out = new ObjectOutputStream(bos);
      out.writeObject(this);
      out.close();
      return bos.toByteArray();

on load:
      ByteArrayInputStream bis = new ByteArrayInputStream(byteArray);
      ObjectInputStream in = new ObjectInputStream(bis);

Can you please answer again to my last question
(sorry for the bothering... :-) )

TimYates

3 questions in one? ;-)

What's the question for the last part?

Why are you trying to serialize the Multipart?

rzvika2

ASKER

Yes, one thing leads to another ;-) (but I raise the points each time...)
The actual question deals with saving and loading an object to byte[], where not all the objects that it contains, are serialized.

Mick Barry

use the code i posted above to serialize your multipart.

TimYates

I don't think you can... That's the point of the Serializable interface, it stops you serializing things that cannot be serialized...

So, you can save the data by using writeTo() as objects showed you, but not load it back in...

Again, why are you serializing the Multipart object? Why not send the data needed to create it, to the place where it is to be used instead?

rzvika2

ASKER

I must save and load object B to byte array (this is not an option).
I save it because I'm not sending it immediately and I don't want to use the files.

Mick Barry

Why don't you save the message details *before* you create your Multipart.
ie. save what you need to create the multipart.

TimYates

I don't believe this can be done... I *think* that you will have to create it when you want to send (as it is not serializable)

I may be wrong though...

Hopefully objects can show you how :-)

rzvika2

ASKER

Someone packs for me this multipart according to a user selection (of files).
I have to save it for a later usage.
I think the most convenient way is to work with serialized object.
Can't I just derive from MimeBodyPart and Multipart and implement them as serializable?

SOLUTION

TimYates

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