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Exception "Invalid URI - The URI Scheme is not VALID" occured while transformation

Posted on 2004-08-26
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3,066 Views
Last Modified: 2012-06-21
Public Function cleanExpXML(ByVal _expXML As String, ByVal _xslFilepath As String) As String
               Try
           Dim expFile_xmlDoc As New xmldocument
            Dim outputXML As String

            ' Load xsl document
            If xslTransformDoc Is Nothing Then
                resolver = New XmlUrlResolver
                resolver.Credentials = CredentialCache.DefaultCredentials
                xslTransformDoc = New XslTransform
                xslTransformDoc.Load(_xslFilepath)            
            End If

            expFile_xmlDoc.LoadXml(_expXML)
            Dim argumentList As XsltArgumentList

            ' Transform the file.
            xslTransformDoc.Transform(_expXML, outputXML, resolver)    'exception occuring here     '_xslFilepath is something  like  d:\www\temp\myxsl.xsl  

            Return outputXML    

        Catch ex As Exception
            Console.WriteLine(ex.ToString)
        End Try
    End Function


i mean,is there any constructor which returns the transformed document as a string INSTEAD of transforming document to a file?


thanks for your reply

regards

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Question by:vihar123
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Accepted Solution

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praveen79 earned 500 total points
ID: 11900878
hi,

try this ....



 Dim strWriter As StringWriter = New StringWriter

  ' Transform the file.
      xslTransformDoc.Transform(expFile_xmlDoc.CreateNavigator(), argumentList, strWriter , resolver)
       outputXML = strWriter .ToString()
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