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kwixFlag for Philippines

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Java to VB6 equivalent syntax

I've been trying to convert this java code to VB6.

function intToHex(i)
 {
  var sHex = "0123456789ABCDEF";      
  h = "";
  i = parseInt(i);      
  for(j = 0; j <= 3; j++) {
    h += sHex.charAt((i >> (j * 8 + 4)) & 0x0F) +
         sHex.charAt((i >> (j * 8)) & 0x0F);
  }
  return h.substring(0,2);
}

Im not really sure but I think the code inside the loop is searching for any matching character(s) that matches any of the enumerated characters in the "sHex" variable (like the built-in Instr VB function). I'm not sure what the "(i >> (j * 8 + 4)" does.--And it is a parameter of charAt. Does the parameter indicate a bit shift? or something else?

It would really help if someone can translate the java function above to a VB6 function. Thanks.


chris

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Colosseo
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Hi

The code above is converting an integer i in to its hex equivalent

in visual basic you can use Hex to get the hex value

for example:

i = 234234

h = Hex(i)

msgbox h

HTH

Scott
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ASKER


I know how to use the built-in Hex conversion function in VB..but obviously, the code above does more besides Hex conversion. as "sHex" is present, i think it is a "pattern" string/character that the function will refer to when executing the code (correct me if im wrong). What confuses me the most is the code inside the loop (see below):

 h += sHex.charAt((i >> (j * 8 + 4)) & 0x0F) +
         sHex.charAt((i >> (j * 8)) & 0x0F);


If anyone can convert the java function to the CORRECT equivalent VB6 function, i'll give the points immediately, and maybe increase it further. Thanks.

Sorry kwix

on second inspection it seems to be doing a bit more

it seems to be reading an integer then converting it to its hex form but in reverse

so for the integer 1234

your function returns sHex as D2040000 and then extracts just the first two characters using the substring .. in this case D2

To properly replicate this you could use a function like this.

Private Function intToHex(i)

  ' Convert the integer to its hex equivalent
  hexnum = Hex(i)

  ' If the hex value has only one character then add a leading 0
  If Len(hexnum) = 1 Then hexnum = "0" & hexnum
 
  ' Return the Last two characters
  intToHex = Right(hexnum, 2)

End Function

This converts the integer to hex but without reversing the order number so it reads the last two characters rather than the first two.

Regards

Scott
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ASKER

ok then.. so what is the purpose of  var sHex = "0123456789ABCDEF"; in the java code?
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Ok, I guess thats the clearest explanation i can have. :)
But VB6 does not have built-in bit shifting. Can you help create the exact function replica in VB6? ..same as the javascript function?

afterwards.. the points are yours.

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ASKER

ok. i got it. thanks. :)