Solved

perl script won't validate

Posted on 2004-08-26
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Last Modified: 2012-06-27
I am trying to get my form to validate. The script should test the input and if there is an error display the @errors, but if the input is correct display a page that shows the results. Everything works except the validation part. When I test it, I don't get any syntax errors. Is there aproblem with my If statement?

The webpage: http://crux.baker.edu/tscott04/public_html/chap06/c06case1.html

The Script:

#assign values to variables
$name = param('Name');
$proj1 = param('Proj1');
$proj2 = param('Proj2');
$midterm = param('Midterm');
$final = param('Final');
$total_score = ($proj1 + $proj2 + $midterm + $final);

#validate input data
if ($proj1 > 50 and $proj1 == "") {
      push(@errors, "Please enter a score between 0-50 for Project 1.");
}
 
if ($proj2 > 50 and $proj2 == "") {
      push(@errors, "Please enter a score between 0-50 for Project 2.");
}


if ($midterm > 100 and $midterm == "") {
      push(@errors, "Please enter a score between 0-100 for Midterm.");
}


if ($final > 100 and $final == "") {
      push(@errors, "Please enter a score between 0-100 for Final.");
}

#determine size of @errors array
$size = @errors;

#process input data or display error page
if ($size == 0) {
      #process input data
#print name and final score to file
open(OUTFILE, ">> c06case1.txt")
      or die "Error opening c06case1.txt. $!, stopped";
print OUTFILE "$name, $total_score\n";
close(OUTFILE);

#generate HTML acknowledgement
print "<HTML>\n";
print "<HEAD><TITLE>Mountain Community College</TITLE></HEAD>\n";
print "<BODY>\n";
print "<H3>A record for $name with a total of $total_score has been saved.</H3>\n";
print "</BODY>\n";
print "</HTML>\n";

}
else {
#display error page
      print "<HTML><HEAD><TITLE>Mountain Community College</TITLE></HEAD>\n";
      print "<BODY>\n";
      print "<H3>Please use your browser's back button to \n";
      print "return to the form to make the following corrections: </H3><BR>\n";
      for(my $x=0; $x<$size; $x+1) {
            print "$errors[$x]<BR>\n";
      }
      print "</BODY></HTML>\n";      


}

0
Comment
Question by:reesecup999
  • 3
4 Comments
 
LVL 84

Accepted Solution

by:
ozo earned 500 total points
ID: 11908840
$proj1 == ""
is a strange way to write
$proj1 == 0

$proj1 > 50 and $proj1 == ""
will never be true
0
 
LVL 84

Expert Comment

by:ozo
ID: 11908901
Perhaps you meant "or" instead of "and"
0
 
LVL 84

Expert Comment

by:ozo
ID: 11908943
Perhaps you also meant "eq" instead of "=="
0
 
LVL 48

Expert Comment

by:Tintin
ID: 11909329
Given that it's an assignment, we can't feed you too much (ozo has already given you plenty).

If you convert the if logic into English you get:

If proj1 is greater than 50 and is blank then set an error message.

Unless you live in a very Zen world, I'm sure you can see the flaw in the logic.
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