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Help!  Writing script to show process id

Posted on 2004-08-27
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Last Modified: 2012-08-13
Hello, I am writing a perl script that will just display the process id given a process name.

Here is a piece of it....

$pid = `ps -ef -o pid,ppid,comm | grep xview | awk '{print $1'}`;
print "pid = $pid\n";

now, when I just run this command via command line-->
ps -ef -o pid,ppid,comm | grep xview | awk '{print $1'}

it prints out only the process id number:
55386

However, when I run it in the script, it prints out:

55386 4593  xview
Am I using the wrong quotes or something?
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Question by:jewee
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3 Comments
 
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Accepted Solution

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rkosai earned 500 total points
ID: 11917809
The problem seems that Perl is using its own $1, which in Perl is the item captured by parenthesis in a regular expression.

You could instead use the system() command, with single quotes.  So instead of:

 $pid = `ps -ef -o pid,ppid,comm | grep xview | awk '{print $1'}`;

It would be:

my $pid = system('ps -ef -o pid,ppid,comm | grep xview | awk \'{print $1\'}'); #note the escaped quotes
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Expert Comment

by:ozo
ID: 11918842
$pid = `ps -ef -o pid,ppid,comm | grep xview | awk '{print \$1'}`;
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LVL 84

Expert Comment

by:ozo
ID: 11919019
#or
$pid = join"\n",map{(split)[0]}grep/xview/,`ps -ef -o pid,ppid,comm`;
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