Still celebrating National IT Professionals Day with 3 months of free Premium Membership. Use Code ITDAY17

x
?
Solved

Upload sound file and store path in database

Posted on 2004-08-29
4
Medium Priority
?
621 Views
Last Modified: 2010-04-01
Dear all,

My website is about learning German language. the administrator can add new exercise question such as dictation. so the admin should specify the path (input type = file) of the sound file.how should i write the jsp code to upload the sound file to web server and store the name of sound file?thanks in avance

0
Comment
Question by:ahwind
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
4 Comments
 
LVL 6

Expert Comment

by:CodingExperts
ID: 11925012
Hi ahwind,
You can see an example on the link
http://www.oop-reserch.com/mime_example_3.html

This example explains:

How to set the maximum size of the file to be uploaded ?
How to restrict the mime-type (Content-Type) of the file to be uploaded. For example, if you'd like to allow the users to upload the files only of audio type? how can you do it?
How to check the binary contents of the uploaded file?

I hope this should suffice ur needs .if in case of any doubt do write back..

Good Luck
Coding Experts
0
 
LVL 6

Expert Comment

by:CodingExperts
ID: 11925023
Hi ahwind,
May be this sample code may help you solve your problem.

<!-- upload.jsp -->
<%@ page import="java.io.*" %>

<%
String contentType = request.getContentType();
System.out.println("Content type is :: " +contentType);
if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) {
DataInputStream in = new DataInputStream(request.getInputStream());
int formDataLength = request.getContentLength();

byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while (totalBytesRead < formDataLength) {
byteRead = in.read(dataBytes, totalBytesRead, formDataLength);
totalBytesRead += byteRead;
}

String file = new String(dataBytes);
String saveFile = file.substring(file.indexOf("filename=\"") + 10);
saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\""));

//out.print(dataBytes);

int lastIndex = contentType.lastIndexOf("=");
String boundary = contentType.substring(lastIndex + 1,contentType.length());
//out.println(boundary);
int pos;
pos = file.indexOf("filename=\"");

pos = file.indexOf("\n", pos) + 1;

pos = file.indexOf("\n", pos) + 1;

pos = file.indexOf("\n", pos) + 1;


int boundaryLocation = file.indexOf(boundary, pos) - 4;
int startPos = ((file.substring(0, pos)).getBytes()).length;
int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;

FileOutputStream fileOut = new FileOutputStream(saveFile);


//fileOut.write(dataBytes);
fileOut.write(dataBytes, startPos, (endPos - startPos));
fileOut.flush();
fileOut.close();

out.println("File saved as " +saveFile);

}
%>
0
 
LVL 6

Accepted Solution

by:
CodingExperts earned 750 total points
ID: 11925036
0
 

Author Comment

by:ahwind
ID: 12037287
Dear CodingExperts,

I have solved my problem regarding the upload file into web server. I used the MultipartRequest class written by Jason Hunter under servlets.com.  Go here to download the jar: http://www.servlets.com/cos/cos-05Nov2002.zip

Put cos.jar in your classpath.  Then write a servlet that accepts the request as a MultipartRequest object and you will be able to pull out the uploaded files... There is lots of documentation on how to use these classes on the internet including here:  http://www.servlets.com/cos/index.html


1) Download the zip and put "cos.jar" on classpath

2) Create an HTML form with upload button in a file called "form.html":

<form action="test.jsp" method="post" enctype="multipart/form-data">
<input type=file name=testfile>
<input type=submit>
</form>

3) Create an empty directory in "c:/upload"

4) Make a file called "test.jsp", and put:

<%@ page import="com.oreilly.servlet.*" %>
<%
 MultipartRequest mp = new MultipartRequest(request, "c:/upload");
 out.println("DONE");
%>

5) The file should have been uploaded.  You can find more command on what you cando with the MultipartRequest here: http://www.servlets.com/cos/javadoc/com/oreilly/servlet/MultipartRequest.html
0

Featured Post

What does it mean to be "Always On"?

Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

A while back, I ran into a situation where I was trying to use the calculated columns feature in SharePoint 2013 to do some simple math using values in two lists. Between certain data types not being accessible, and also with trying to make a one to…
Are you an Exchange administrator employed with an organization? And, have you encountered a corrupt Exchange database due to which you are not able to open its EDB file. This article will explain all the steps to repair corrupt Exchange database.
Monitoring a network: how to monitor network services and why? Michael Kulchisky, MCSE, MCSA, MCP, VTSP, VSP, CCSP outlines the philosophy behind service monitoring and why a handshake validation is critical in network monitoring. Software utilized …
Visualize your data even better in Access queries. Given a date and a value, this lesson shows how to compare that value with the previous value, calculate the difference, and display a circle if the value is the same, an up triangle if it increased…

688 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question