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Date Manipulation in PL/SQL

Posted on 2004-08-30
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Last Modified: 2012-05-05
Hi,

I'm trying to wright a script to take an oracle date and substract both 1 second and 2 seconds from it.

Here's my solution which works on my test database but not on production.

to_char(lAvailableCycleIterCurRec.END_DATE_TIME-1.1574074074074074074074074074074e-5,'yyyymmddhh24miss'));

Any help much appreciated.

Thanks,

Derek.
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Question by:ruamire
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Accepted Solution

by:
cjjclifford earned 130 total points
ID: 11929590
What you've done is the equivalent to:

to_char(lAvailableCycleIterCurRec.END_DATE_TIME - ( 1 / ( 24 * 60 * 60 ) ), 'yyyymmddhh24miss' )

which is correct... what (if any) error is being produced on production, in comparision to Test, or describe what differences there are...
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Assisted Solution

by:pratikroy
pratikroy earned 120 total points
ID: 11929912
Hi Derek,

what is the problem that u encounter on production ? Do you get an error ? if so, what error? If you dont get the desired result, then what is the result that you get ?

Have you checked whether the data type of the column - lAvailableCycleIterCurRec.END_DATE_TIME is same on TEST and PRODUCTION databases ?

Cheers !
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Expert Comment

by:pratikroy
ID: 11929936
Can you try the following :

ALTER SESSION SET NLS_DATE_FORMAT='YYYY-MON-DD HH24:MI:SS';

Select lAvailableCycleIterCurRec.END_DATE_TIME,
         lAvailableCycleIterCurRec.END_DATE_TIME-1.1574074074074074074074074074074e-5
From TableA;

Select sysdate, sysdate - 1.1574074074074074074074074074074e-5 from dual;

Hope this helps !

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Author Comment

by:ruamire
ID: 11930029
I've changed it now to

to_date(lAvailableCycleIterCurRec.END_DATE_TIME, 'yyyymmddhh24miss' ) - (1/24/60/60));

The problem was that new date format came in, previously only the date was specified, now they specified date and time and our conversion was only 'yyyymmddhhmiss', not 'yyyymmddhh24miss'.

It caused problems all over the place!

Thanks for you help

Derek.
0

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