i urgently need the answer to this..

A /27 network has just 7 computers with unique IP addresses on the network. How many IP addresses are unused within this network?

ganatra..
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Commented:
30 minus the 7 = 23 unused
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Commented:
Nie free IPs should be left if it is a /27 network really... I'm answering but I'm 100% sure this is homework or a similar task. Or are you too lazy to google?
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Commented:
Ehm...

Nine free IPs.

For me it's 16 - 7 used = 9.

Where do the 30 come from lrmoore?
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Technical ConsultantCommented:
sounds a bit like homework to me?
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Commented:
/27 network leaves 5 bits for host portion.  2^5=32.  -2 for network and broadcast = 30.  30 - 7 used =23.
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Commented:
27 DEC = 00011011 BIN

4 bits for host portion?

2^4=16

Forgot -2 for network & broadcast

16 - 2 = 14

14 - 7 used = 7 then?
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Commented:
Mcwojtekk, it's like this:  nnnnnnnn.nnnnnnnn.nnnnnnnn.nnnhhhhh  The N's are Network bits and the H's are host bits.  It has nothing to do with 27 decimal = 00011011 in binary.
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Author Commented:
i just wanted to know that 7 will be unused or the network and broadcast will also come in the unused..

i think 7 will be termed as unused...right.

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Commented:

There 32-2-7 = 23.  But if you are using DHCP, then I would suggest only using another 7-8 more.  I try to keep DHCP networks to 50%
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Commented:
Ganatra, please accept the best answer to hand out points. (Certainly not mine :-)
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Author Commented:
its fine mcwojtekk... everybody is a learner.. one who considers himself perfect.. doesnt know anything..

take care..
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