Solved

IP Addresses

Posted on 2004-08-30
11
317 Views
Last Modified: 2011-09-20
i urgently need the answer to this..

A /27 network has just 7 computers with unique IP addresses on the network. How many IP addresses are unused within this network?

plz reply now..

ganatra..
0
Comment
Question by:ganatra
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 4
  • 2
  • 2
  • +3
11 Comments
 
LVL 79

Accepted Solution

by:
lrmoore earned 30 total points
ID: 11931084
30 minus the 7 = 23 unused
0
 
LVL 8

Expert Comment

by:Wojciech Duda
ID: 11931088
Nie free IPs should be left if it is a /27 network really... I'm answering but I'm 100% sure this is homework or a similar task. Or are you too lazy to google?
0
 
LVL 8

Expert Comment

by:Wojciech Duda
ID: 11931105
Ehm...

Nine free IPs.


For me it's 16 - 7 used = 9.

Where do the 30 come from lrmoore?
0
Microsoft Certification Exam 74-409

Veeam® is happy to provide the Microsoft community with a study guide prepared by MVP and MCT, Orin Thomas. This guide will take you through each of the exam objectives, helping you to prepare for and pass the examination.

 
LVL 57

Expert Comment

by:Pete Long
ID: 11931143
sounds a bit like homework to me?
0
 
LVL 27

Assisted Solution

by:pseudocyber
pseudocyber earned 20 total points
ID: 11931161
/27 network leaves 5 bits for host portion.  2^5=32.  -2 for network and broadcast = 30.  30 - 7 used =23.
0
 
LVL 8

Expert Comment

by:Wojciech Duda
ID: 11931260
27 DEC = 00011011 BIN

4 bits for host portion?

2^4=16

Forgot -2 for network & broadcast

16 - 2 = 14

14 - 7 used = 7 then?
0
 
LVL 27

Expert Comment

by:pseudocyber
ID: 11931342
Mcwojtekk, it's like this:  nnnnnnnn.nnnnnnnn.nnnnnnnn.nnnhhhhh  The N's are Network bits and the H's are host bits.  It has nothing to do with 27 decimal = 00011011 in binary.
0
 

Author Comment

by:ganatra
ID: 11931597
i just wanted to know that 7 will be unused or the network and broadcast will also come in the unused..

i think 7 will be termed as unused...right.

thx for the answers..
0
 
LVL 15

Expert Comment

by:adamdrayer
ID: 11931743

There 32-2-7 = 23.  But if you are using DHCP, then I would suggest only using another 7-8 more.  I try to keep DHCP networks to 50%
0
 
LVL 8

Expert Comment

by:Wojciech Duda
ID: 11931829
Ganatra, please accept the best answer to hand out points. (Certainly not mine :-)
0
 

Author Comment

by:ganatra
ID: 11931900
its fine mcwojtekk... everybody is a learner.. one who considers himself perfect.. doesnt know anything..

thx for all the answers..

take care..
0

Featured Post

Don't Miss ATEN at InfoComm 2017!

Visit booth #2167 to see the  new ATEN VM3200 32 x 32 Modular Matrix Switch. Other highlights include the VE8950 4K HDMI Over IP Extender, VS1912 12-Port DP Video Wall Media Player  and VK2100 ATEN Control System. Register now with Free Pass Code ATEN288!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Resolve DNS query failed errors for Exchange
WARNING:   If you follow the instructions here, you will wipe out your VTP and VLAN configurations.  Make sure you have backed up your switch!!! I recently had some issues with a few low-end Cisco routers (RV325) and I opened a case with Cisco TA…
This video gives you a great overview about bandwidth monitoring with SNMP and WMI with our network monitoring solution PRTG Network Monitor (https://www.paessler.com/prtg). If you're looking for how to monitor bandwidth using netflow or packet s…
In this video we outline the Physical Segments view of NetCrunch network monitor. By following this brief how-to video, you will be able to learn how NetCrunch visualizes your network, how granular is the information collected, as well as where to f…

688 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question