?
Solved

problem with calling a servlet from a javascript using window.location

Posted on 2004-08-31
3
Medium Priority
?
895 Views
Last Modified: 2008-01-09
I am calling a servlet from a javascript using the following code:

pageUrl  = "/servlet/Main?ReportID=ADD&year=" + year1 + "&field2=" + field2 (etc, etc, etc)

location.replace('" "');
window.location = pageUrl;
return true:

i use this code all the time, but this time I am sending TONS of data, and it errors on the window.location line.  I am pretty sure it's because of the amount of data that I'm sending via the url.  I tested by limiting the amount of data and it works, but when I send all the data that is needed, it freaks out
with a javascript error that can't be captured and gives me a "page not found" error with the following in the url:

/servlet/"%20"

when it should be /servlet/Main?ReportID=ADD&year=2004&field2=field2 (etc, etc, etc)

Is there a limit to the amount of characters in a url?  And if so, how can I pass all my data to the servlet using a javascript?  Can I use putsession commands in a servlet?

HELP!


0
Comment
Question by:donz4
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
3 Comments
 
LVL 19

Accepted Solution

by:
ramazanyich earned 750 total points
ID: 11947803
the length of query string can vary depending on the server. Some servers end reading it from 1024 byte. In general it is not recommended to use parameters in URL if it will be a big one. Better use hidden  form with POST method and filling hidden values by javascript and calling form.submit() function from javascript.
So in your case it javascript  can be:
document.hh.ReportID.value="ADD";
document.hh.year.value="2004";
document.hh.field2.value="field2";
//...
document.hh.submit();



and HTML:
<form name="hh" method="POST" action="/servlet/Mail">
<input type="hidden" name="ReportID"/>
<input type="hidden" name="year"/>
<input type="hidden" name="field2"/>
<!-- add other input elements for other parameters -->

</form>

0
 
LVL 11

Expert Comment

by:sompol_kiatkamolchai
ID: 11948427
Please check this first.

pageUrl  = "/servlet/Main?ReportID=ADD&year=" + year1 + "&field2=" + field2 (etc, etc, etc)

I think there is one space in

"/servlet/ Main?......
            ^
             There is one space here!
0
 
LVL 11

Expert Comment

by:raj3060
ID: 11966676
If it is working fine with less data, then there nothing wrong with the code. I would say send data in array. That will be faster and easier.
--Raj
0

Featured Post

What does it mean to be "Always On"?

Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

In the absence of a fully-fledged GPO Management product like AGPM, the script in this article will provide you with a simple way to watch the domain (or a select OU) for GPOs changes and automatically take backups when policies are added, removed o…
The top devops trends for 2017 are focused on improved deployment frequency, decreased lead time for change and decreased MTTR.
Sometimes it takes a new vantage point, apart from our everyday security practices, to truly see our Active Directory (AD) vulnerabilities. We get used to implementing the same techniques and checking the same areas for a breach. This pattern can re…
In this video, Percona Director of Solution Engineering Jon Tobin discusses the function and features of Percona Server for MongoDB. How Percona can help Percona can help you determine if Percona Server for MongoDB is the right solution for …
Suggested Courses
Course of the Month9 days, 7 hours left to enroll

762 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question