ADDRESS OVERLAP

Hi

I'm using 10.1.1.2 for ethernet and 10.0.0.1 for serial0 and am getting address overlap error, what should I do ?
kamal73Asked:
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Don JohnstonInstructorCommented:
Use a 16 (255.255.0.0) or 24 bit (255.255.255.0) mask.

-Don
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kamal73Author Commented:
remote router that I am trying to connect with via serial port has a 8 bit mask
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Don JohnstonInstructorCommented:
I assume that the remote router is off the serial 0 interface...

If you can't change the mask on that device, you'll have to use a different (non-10.x.x.x) address on the Ethernet interface.

-Don
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kamal73Author Commented:
I've even tried giving it 16 bit mask it still comes back with the same error,
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MarkDozierCommented:
is the serial  10.0.0.1 255.0.0.0
and the e0    10.1.1.2 255.0.0.0 or 10.1.1.2 255.255.255.0?

I will read this in the lab tomorrow ans see what happens
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kamal73Author Commented:
well either way, no matter which way I try it just won't let me have another 10 network on the same router for any interface, for instance if I try 11.0.0.1 255.0.0.0 it would allow it .
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Don JohnstonInstructorCommented:
Here's another way.

serial0 10.0.0.1 255.255.255.0

ethernet0 10.1.1.2 255.255.255.0

It ain't pretty, but it'll work. ;-)

-Don
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lrmooreCommented:
Both ends of the serial link must match.
It the remote end is 255.0.0.0, unless you can convince the other end to change, then you have no choice but to use the same mask on your end, and you then cannot use any 10.x.x.x subnet on your Ethernet port.
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PennGwynCommented:
Odds are good that the serial port will work fine with a longer mask, as long as the address on that port is close enough to the address of the remote router.

However:  Serial connections are, by their nature, connections with only two devices on them, and so can be adequately addressed by a /30 block, or even left unnumbered.  An admin who puts a /8 address on such a link should be reassigned to some other line of work -- perhaps with Microsoft, who see nothing wrong with using 10.0.0.0/8 for a second loopback address....  A /8 block provides addressing for 16 million hosts.

RFC 1918 defines three sets of private addresses:  10.0.0.0/8, 172.16.0.0-172.31.0.0/16, and 192.168.0.0-192.168.255.0/24.
Since 10.0.0.0/8 has been taken for the serial link, use one of the other ranges for your Ethernet side.

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kamal73Author Commented:
PennGwn

This is not an official address it's only lab environment, and I can change the other side ip address and mask if I want to. I just want to know why even though I am using completely different subnets here on each interface it thinks that it is overlaping.
No matter what mask I use it still gives the same error message. Can anyone try this on your lab routers.
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lrmooreCommented:
As long as you are using an 8-bit mask on one interface, i.e.
10.x.x.x 255.0.0.0
Then no matter what you do, you cannot use any 10.x.x. / 255.255.255.0 or whatever else mask you want.

interface Ethernet 0/0
  ip address 10.10.10.1 255.255.255.0

interface Ethernet 0/1
  ip address 10.10.11.1 255.255.255.0

interface Serial 2/0
  ip address 10.10.12.1 255.255.255.252

interface Serial 2/1
  ip address 10.10.12.5 255.255.255.252

interface Serial 2/2
  ip address 10.10.20.1 255.0.0.0
% 10.0.0.0 overlaps with Ethernet0/1

interface Serial 2/2
  ip address 11.10.12.1 255.0.0.0
<OK!>

Everything is working as designed. I don't understand what your question is.

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kamal73Author Commented:
it's strange you don't understand my question but you have managed to answe it :-)
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Don JohnstonInstructorCommented:
What was the question? I thought you just wanted to make it work.

-Don
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