Solved

Datagrid with Multiple Select Checkboxes

Posted on 2004-09-02
1
272 Views
Last Modified: 2011-09-20
Hi,

I have a datagrid with a list of items, and I want to be able to have a column that contains checkboxes and then a button below that postbacks. On postback, I want to be able to determine which rows were checked. How can I do this without a postback for each checkbox being checked?

Thanks!
0
Comment
Question by:tonypino123
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
1 Comment
 
LVL 17

Accepted Solution

by:
AerosSaga earned 500 total points
ID: 11964326
<%@ Page Language="vb" AutoEventWireup="false" Codebehind="WebForm1.aspx.vb" Inherits="RadioButtonInDataGrid.WebForm1"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
      <HEAD>
            <title>WebForm1</title>
            <meta name="GENERATOR" content="Microsoft Visual Studio.NET 7.0">
            <meta name="CODE_LANGUAGE" content="Visual Basic 7.0">
            <meta name="vs_defaultClientScript" content="JavaScript">
            <meta name="vs_targetSchema" content="http://schemas.microsoft.com/intellisense/ie5">
      </HEAD>
      <body MS_POSITIONING="GridLayout">
            <form id="Form1" method="post" runat="server">
                  <asp:DataGrid id="DataGrid1" style="Z-INDEX: 101; LEFT: 8px; POSITION: absolute; TOP: 8px" runat="server" BorderColor="#CC9966" BorderStyle="None" BorderWidth="1px" BackColor="White" CellPadding="4" AutoGenerateColumns="False" Width="144px" Height="22px">
                        <SelectedItemStyle Font-Bold="True" ForeColor="#663399" BackColor="#FFCC66"></SelectedItemStyle>
                        <ItemStyle ForeColor="#330099" BackColor="White"></ItemStyle>
                        <HeaderStyle Font-Bold="True" ForeColor="#FFFFCC" BackColor="#990000"></HeaderStyle>
                        <FooterStyle ForeColor="#330099" BackColor="#FFFFCC"></FooterStyle>
                        <Columns>
                              <asp:TemplateColumn HeaderText="Select">
                                    <ItemTemplate>
                                          <asp:Label id="Label2" runat="server"></asp:Label>
                                    </ItemTemplate>
                              </asp:TemplateColumn>
                              <asp:BoundColumn DataField="lastname" HeaderText="Last Name"></asp:BoundColumn>
                        </Columns>
                        <PagerStyle HorizontalAlign="Center" ForeColor="#330099" BackColor="#FFFFCC"></PagerStyle>
                  </asp:DataGrid>
                  <asp:Label id="Label3" style="Z-INDEX: 103; LEFT: 222px; POSITION: absolute; TOP: 35px" runat="server" Width="184px"></asp:Label>
                  <asp:Button id="Button1" style="Z-INDEX: 102; LEFT: 218px; POSITION: absolute; TOP: 70px" runat="server" Text="Display Selected Value"></asp:Button>
            </form>
      </body>
</HTML>

----------------------------------------------------------------------------------------------------------------------

Private Sub Page_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
        If Not Page.IsPostBack Then
            BindGrid()
        End If
    End Sub

    Sub BindGrid()
        Dim connstr As String = "Integrated Security=SSPI;Initial Catalog=Northwind;Data Source=.\NetSDK"
        Dim cnn As SqlConnection
        Dim da As SqlDataAdapter
        Dim ds As New DataSet()
        cnn = New SqlConnection(connstr)
        da = New SqlDataAdapter("select * from employees", cnn)
        da.Fill(ds, "employees")
        DataGrid1.DataSource = ds
        DataGrid1.DataBind()
    End Sub

    Private Sub DataGrid1_ItemDataBound(ByVal sender As Object, ByVal e As System.Web.UI.WebControls.DataGridItemEventArgs) Handles DataGrid1.ItemDataBound
        If e.Item.ItemType = ListItemType.AlternatingItem Or e.Item.ItemType = ListItemType.Item Then
            Dim r As Label
            r = e.Item.FindControl("Label2")
            r.Text = "<input type=radio name='myradiogroup' value=" & e.Item.Cells(1).Text & ">"
        End If
    End Sub

    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
        Label3.Text = Request.Form("myradiogroup")
        Dim i As DataGridItem
        For Each i In DataGrid1.Items
            If i.ItemType = ListItemType.AlternatingItem Or i.ItemType = ListItemType.Item Then
                Dim r As Label
                r = i.FindControl("Label2")
                If r.Text.IndexOf(Label3.Text) > 0 Then
                    r.Text = "<input type=radio name='myradiogroup' value=" & i.Cells(1).Text & " checked>"
                Else
                    r.Text = "<input type=radio name='myradiogroup' value=" & i.Cells(1).Text & ">"
                End If
            End If
        Next
    End Sub
0

Featured Post

Online Training Solution

Drastically shorten your training time with WalkMe's advanced online training solution that Guides your trainees to action. Forget about retraining and skyrocket knowledge retention rates.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

One of the pain points with developing AJAX, JavaScript, JQuery, and other client-side behaviors is that JavaScript doesn’t allow for cross domain request for pulling content. For example, JavaScript code on www.johnchapman.name could not pull conte…
A quick way to get a menu to work on our website, is using the Menu control and assign it to a web.sitemap using SiteMapDataSource. Example of web.sitemap file: (CODE) Sample code to add to the page menu: (CODE) Running the application, we wi…
There are cases when e.g. an IT administrator wants to have full access and view into selected mailboxes on Exchange server, directly from his own email account in Outlook or Outlook Web Access. This proves useful when for example administrator want…
In this brief tutorial Pawel from AdRem Software explains how you can quickly find out which services are running on your network, or what are the IP addresses of servers responsible for each service. Software used is freeware NetCrunch Tools (https…

728 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question