Link to home
Start Free TrialLog in
Avatar of theswally
theswally

asked on

T-SQL Loop through recordset and UPDATE based on every record

I'm brand new to T-SQL and need some help.  I'm using 2 tables.  One is called Receivers, and looks like this:

RECEIVERS
ID, [Account ID], R00
1, 0, 123
2, 0, 456
3, 0, 789

The other is called RecAccountID and looks like this:
RECACCOUNTID
ID, R00
100,123
101,456
102,789

I need to update the Receivers table [Account ID] column with the value from ID in the RecAccountID table, where they are matched on R00.  So the Receivers table needs to look like this:
RECEIVERS
ID, [Account ID], R00
1, 100, 123
2, 101, 456
3, 102, 789

Here's what I have so far:
=====================================
declare @accountID int, @recid int, @recr00 varchar(12)

declare rec_cursor CURSOR FOR
select id, r00
from receivers
where [account id] = 999999

OPEN rec_cursor

FETCH NEXT FROM rec_cursor
INTO @recid, @recr00

WHILE @@FETCH_STATUS = 0
BEGIN
      declare account_cursor FOR
      select ID
      FROM RecAccountID
      WHERE r00 = @recr00

      OPEN account_cursor

      FETCH NEXT FROM account_cursor
      INTO @accountID

      UPDATE Receivers
      SET [Account ID] = idfromabove
      WHERE ID = @accountID

      CLOSE account_cursor
      DEALLOCATE account_cursor

      FETCH NEXT FROM rec_cursor
      INTO @recid, recr00
END

CLOSE rec_cursor
DEALLOCATE rec_cursor
GO
=====================================
It's probably totally wrong.  Anyone give me some help on this?  Thanks.

Bret
ASKER CERTIFIED SOLUTION
Avatar of SjoerdVerweij
SjoerdVerweij

Link to home
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Start Free Trial
This should work also.

update RECEIVERS
set [Account_ID] = (select RECACCOUNTID.ID
                             from RECACCOUNTID
                             where RECACCOUNTID.R00 = RECEIVERS.R00)
Avatar of theswally
theswally

ASKER

I tried that first, ItsTheRide, but that didn't work for me in SQL Server.

Thanks, Sjoerd!