Solved

Sorting INNER JOIN

Posted on 2004-09-04
7
411 Views
Last Modified: 2007-12-19
My problem lies here:

I have a message board running on MS-SQL. I want to sort the topics in order of last reply. I have a TOPICS table, USERNAMES table and a POSTS table. To display an asp page, I need to get the thread title, thread id, username of last person to reply and order these results by time of last reply. Ideally, this should be one sql statement but I can't get it to work.

I'm assuming this is going to take a subquery to get the latest post where POSTS.thread_id is the same as the thread id.

Can anyone help?
0
Comment
Question by:thefritterfatboy
  • 3
  • 2
  • 2
7 Comments
 
LVL 11

Expert Comment

by:ram2098
ID: 11980794
I am not sure of your table structures..but your query should be something like this.

I assume TOPICS and POSTS table are related bt THREAD_ID
and POSTS AND USERNAMES are related by USERID

then your query is as below..... (You can include a where clause to this if you want the details for a specific topic or user etc)

SELECT A.THREADID,
            A.THREADTITLE,
            C.USERNAME
FROM TOPICS A
INNER JOIN POSTS B
A.THREAD_ID = B.THREAD_ID
INNER JOIN USERNAMES C
B.USERID = C.USERID
ORDER BY B.POSTTIME DESC

If you can give your table structures in detail ...I can help you with the exact query.
0
 
LVL 15

Expert Comment

by:jdlambert1
ID: 11980813
You need to use JOIN's something like this (I guessed at some of the column names). The WHERE clause uses a variable if you want to restrict it to one thread. The t, u, and p are aliases for the table names so you don't have to type the whole names over and over.

SELECT p.thread_id, p.thread_title, u.LastName
FROM Topics t
 INNER JOIN Posts p ON t.topic_id = p.topic_id
 INNER JOIN UserNames u ON p.user_id = u.user_id
WHERE p.thread_id = @thread_id
ORDER BY p.PostDate DESC

If you want the exact SQL for your specific case, we'll need you to post the column names for each table, and which columns are primary and foreign keys.
0
 
LVL 15

Expert Comment

by:jdlambert1
ID: 11980815
Sorry, ram, I must have started right before you posted...
0
Ransomware-A Revenue Bonanza for Service Providers

Ransomware – malware that gets on your customers’ computers, encrypts their data, and extorts a hefty ransom for the decryption keys – is a surging new threat.  The purpose of this eBook is to educate the reader about ransomware attacks.

 
LVL 10

Author Comment

by:thefritterfatboy
ID: 11980833
That's going to give me a massive recordset of threads mixed in with posts. I only need one record per thread, that's where my problem lies.

The statement SELECT TOP 1 PostDate, postUserID FROM POSTS ORDER BY PostDate DESC; needs to grab the last post and use that if you get what I mean.
0
 
LVL 15

Expert Comment

by:jdlambert1
ID: 11980852
Whoops, I think ram and I both missed that you only want the user name of the last person to post, so I think you'll need a couple of nested sub-selects, similar to this.

SELECT DISTINCT p.thread_id, p.thread_title, u.LastName
FROM Topics t
 INNER JOIN Posts p ON t.topic_id = p.topic_id
 INNER JOIN (
   --get user name of last person to post to a thread
   SELECT thread_id, username
   FROM Posts p INNER JOIN (
      --last post per thread
      SELECT topic_id, Max(thread_id) as Max_thread_id
      FROM Posts
      GROUP BY topic_id
      ) sub ON p.topic_id = sub.topic_id AND p.thread_id = sub.Max_thread_id
   ) u ON p.user_id = u.user_id
WHERE p.thread_id = @thread_id --optional line
0
 
LVL 11

Accepted Solution

by:
ram2098 earned 500 total points
ID: 11980913
you can write it this way too...

SELECT A.THREADID,
            A.THREADTITLE,
            C.USERNAME
FROM TOPICS A
INNER JOIN POSTS B
A.THREAD_ID = B.THREAD_ID
INNER JOIN USERNAMES C
B.USERID = C.USERID
WHERE B.POSTTIME = (SELECT MAX(POSTTIME) FROM POSTS WHERE THREAD_ID = A.THREAD_ID)
ORDER BY B.POSTTIME DESC
0
 
LVL 10

Author Comment

by:thefritterfatboy
ID: 11983851
Using ram2098's sugeestion the solution appears to lie in this SQL:

SELECT T.thread_id,
       T.thread_title,
       U.username,
       U.user_id,
       P.post_time
FROM TVERSION4 T
INNER JOIN PVERSION4 P ON
P.from_thread_id = T.thread_id
INNER JOIN USERS U
ON P.post_user_id = U.user_id
WHERE P.post_time = (SELECT MAX(S.post_time) FROM PVERSION4 S
WHERE S.from_thread_id = T.thread_id)
ORDER BY P.post_time DESC

jdlambert - I'm accepting ram's solution as it makes less queries, space and looks neater! I appreciate your time and effort, however.
0

Featured Post

PRTG Network Monitor: Intuitive Network Monitoring

Network Monitoring is essential to ensure that computer systems and network devices are running. Use PRTG to monitor LANs, servers, websites, applications and devices, bandwidth, virtual environments, remote systems, IoT, and many more. PRTG is easy to set up & use.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
sql 2014,  lock limit 5 32
Need some help to cast ntext to nvarchar SQL 2000 7 34
Increment column based of a FK 8 23
SQL invalid column name 5 14
I wrote this interesting script that really help me find jobs or procedures when working in a huge environment. I could I have written it as a Procedure but then I would have to have it on each machine or have a link to a server-related search that …
Nowadays, some of developer are too much worried about data. Who is using data, who is updating it etc. etc. Because, data is more costlier in term of money and information. So security of data is focusing concern in days. Lets' understand the Au…
This videos aims to give the viewer a basic demonstration of how a user can query current session information by using the SYS_CONTEXT function
Viewers will learn how to use the UPDATE and DELETE statements to change or remove existing data from their tables. Make a table: Update a specific column given a specific row using the UPDATE statement: Remove a set of values using the DELETE s…

832 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question