• C

strncat function

I wrote the below function

char dest[5] = "The ";
char src[10]="aeroplane";
printf("%s\n", strncat(dest, src, 9)); /* problem */
concatenate num number of characters from src to dest
If num >= strlen(src), the whole string will be appended
char *strncat(char *dest, const char *src, int num)
      /* save start of dest to return later */
      char *ptr = dest;

      /* point dest to null terminator in dest */
      dest = (char *)(dest + strlen(dest));

      /* copy from src string to dest string until num==0 or src==null */
      while ( num && *src )
            *dest = *src;  /* copy value */
            dest++;               /* move to next */
            src++;               /* move to next */

      *dest = '\0';      /* set to NULL for last character */
      dest = ptr;            /* move pointer back to start */

      return ptr;

The strncat in string,h will work for above but not my strncat. The reason is dest is declared as char dest[5] and cannot hold more than 5 number of characters.

Can someone suggest me how to solve this?
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efnConnect With a Mentor Commented:
I don't think the problem is in your strncat function.  The problem is that your test case shouldn't work, and if it worked with the library strncat, that was just luck.

As you said, dest is an array of 5 characters, so when you append 10 characters to it, the data is likely to clobber something else, and you get undefined behavior.

So I suggest you make the dest array big enough to hold what you want to store in it.  Then I think you will find that your strncat function works.

You might want to make the num parameter unsigned, or else check it for a negative value.  The standard type is size_t, which is unsigned.


you could make ptr a static variable of fixed length, say:

static char ptr[1001]; /* maximum of 1000 characters for the joined strings */

your code would be like:
1. copy dest to ptr. result: ptr = dest
2. add src to ptr. result: ptr = dest + src
3. return ptr.

1. dest and src would be unchanged.
2. if you need to save the concatenated strings to some variable, you have to take the responsibility that it doesn't mess up your memory. so:

a = strncat(b, c)

hope this helps.

- rael

Kyle AbrahamsSenior .Net DeveloperCommented:
Not sure if you can do this but can you malloc(sizeof(dest) + sizeof(src)) in a new char array, then printf from there?
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Kyle AbrahamsSenior .Net DeveloperCommented:
similiar to what realrael just said, but dynamic.  Sorry, 3:30AM, time for bed.
You shouldnt be calling strncat with that "5" !!!

The whole point of strncat is to not overflow the destination array.  You should always use "sizeof dest" as the third parameter.

Another problem, your strncat is incorrect,, in at least three ways:

(1) .  It will store up to "num" characters past the current end of "dest".  That is wrong, the definition is to limit the TOTAL length of dest to "num" characters.

(2)  It first stores a character past the end of dest, and THEN checks to see if there is any room left.

(3) It always stores a '\0' past "num" characters, even if there isnt room for it.

grg99, you must be thinking of some other function.

The third parameter to strncat limits the number of characters copied, not the total length of the resulting string.

So there is no concept of "room left," and if num and *src are both non-zero, it is correct to move a character.

It is also correct to store a null character after moving num characters.

Egads, you're right, I was thinking of strncpy(). !!  Apologies.

Still it would be nice to have a "safe" version of strcat that doesnt overlow its destination....



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