Solved

Change String

Posted on 2004-09-07
13
202 Views
Last Modified: 2010-04-15
Let's suppose I have got a string like this
char mystring[]="this is wow, hehe... okok.. that's good!";

Are there ways to remove all punctuations excluding apostrophe from the string? The resulting string should be something like this.
"this is wow hehe okok that's good"


Thanks a lot.
0
Comment
Question by:ee_guest
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13 Comments
 
LVL 11

Expert Comment

by:griessh
ID: 11999107
Hi networth10,

Something like

#include <iostream>

void main()
{
   char mystring[]="this is wow, hehe... okok.. that's good!";
   printf ("%s\n", mystring);
   int i = 0;
   char c=mystring[i];
   while (c!='\0') {
       if ( (c>='0' && c<='9') || (c>='A' && c<='z') || (c==' ')) printf ("%c",c);
       c=mystring[++i];
   }
   printf("\n");
}

======
Werner
0
 
LVL 11

Expert Comment

by:griessh
ID: 11999159
>> excluding apostrophe

ooops, ad another "|| (c==0x27)" to the list of exclusions
0
 
LVL 11

Expert Comment

by:griessh
ID: 11999196
Oh well, and since it is C make it:

#include <stdio.h>

int main()

<sigh>
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LVL 46

Expert Comment

by:Sjef Bosman
ID: 11999729
0x027 (escape) shoyld be plain 27

You could include <ctype.h>, then you get

#include <ctype.h>
#include <stdio.h>

int main()
{
    char mystring[]="this is wow, hehe... okok.. that's good!";
    char *ptr= mystring;

    printf ("%s\n", mystring);
    for(; *ptr; ptr++)
        if (!ispunct(*ptr))
            putchar(*ptr);
    putchar('\n');
    return 0;
}
0
 
LVL 11

Expert Comment

by:griessh
ID: 11999914
"ispunct()" includes the apostrophy and that was an exception :-(

0x27 is the right character, because I wanted to exclude the apostrophy, not the escape

I was thinking about using a pointer, but for the understanding it just makes more sense to work with members of an array.

=====
Werner
0
 
LVL 9

Expert Comment

by:jhshukla
ID: 12002433
editing sjef's code:
for(; *ptr; ptr++)
    if (!ispunct(*ptr) || (*ptr == '\''))
        putchar(*ptr);
putchar('\n');
0
 

Author Comment

by:ee_guest
ID: 12002445
Thanks all for the input :)
I wish to store the final string in a variable somewhere (not displaying it).

Sorry for all the misunderstanding.
0
 
LVL 11

Expert Comment

by:avizit
ID: 12003287
so have another array

char A[Max]   ;  /* Max is maximum length of the string */

so just change sjefs modified  code to
i = 0;
for(; *ptr; ptr++, i++)
    if (!ispunct(*ptr) || (*ptr == '\''))
    A[i] = *ptr;



0
 

Author Comment

by:ee_guest
ID: 12003406
avizit, thanks for the input..

But i need a function to do that stripping of characters. Because of that, we are not certain of the max size of the array.
0
 
LVL 84

Accepted Solution

by:
ozo earned 100 total points
ID: 12003424
char *p0,*p1;
for(p0=p1=mystring; *p1=*p0++;){ if( !ispunct(*p1) || (*p1 == '\'')) ){ p1++; } }
0
 
LVL 9

Expert Comment

by:jhshukla
ID: 12006385
char oldStr[] = "whatever";
char *newStr = malloc(sizeof(strlen(oldStr))), *ptr = oldStr;
int i=0;
for(; *ptr; ptr++){
  if(!ispunct(*ptr) || (*ptr != '\''))
    newStr[i++] = *ptr;
}

I used strlen instead of sizeof because oldStr could be char*.
0
 

Author Comment

by:ee_guest
ID: 12006828
ozo,
can you explain the below?


#include <stdio.h>
#include <ctype.h>
#include <string.h>

void strip_string(char *string);

void main()
{
      char mystring[] = "this is.";

      strip_string(mystring);   /* working */
      strip_string("This is."); /* not working */
      printf("%s\n", mystring);
}

void strip_string(char *string)
{
      char *p0,*p1;
      for ( p0=p1=string; *p1=*p0++; )
      {
            if( !ispunct(*p1) || (*p1 == '\'') )
            {
                  p1++;
            }
      }
}
0
 
LVL 11

Expert Comment

by:griessh
ID: 12007346
That's a side effect of ozo's method. strip string is re-using the input string. When you use "This is." as input you pass in a constant which can't be changed.

=====
Werner
0

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