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Dump to text file in winbatch

I am looking for a way to print the contents of a directory to a text
file using winbatch.

 Here is what I have currently.

DirChange("\\mxbiis01\c$\ftp\LocalUser\dkftp")
Handle=FileOpen("C:\list.txt","WRITE")
FileWrite(handle,"FileItemPath")
FileItemPath("*.*")   ; get file list
FileClose(handle)

I know the problem is with the filewrite command.

Any suggestions
0
healthcheckinc
Asked:
healthcheckinc
  • 2
1 Solution
 
void_mainCommented:
Hi healthcheckinc!

I suggest this way:

instead of
-------------------8<---------------------------------------
DirChange("\\mxbiis01\c$\ftp\LocalUser\dkftp")
Handle=FileOpen("C:\list.txt","WRITE")
FileWrite(handle,"FileItemPath")
FileItemPath("*.*")   ; get file list
FileClose(handle)
-------------------8<---------------------------------------


write this code
-------------------8<---------------------------------------
ShellExecute("dir", ">c:\list.txt", "\\mxbiis01\c$\ftp\LocalUser\dkftp", @NORMAL, "")
-------------------8<---------------------------------------

this invokes a system call and forces the "dir" command to write the output to the textfile.
The disadvantage is, the dir command writes additional information to that file.

regards
void_main
0
 
void_mainCommented:
Good suggest @venabili
0
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