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Small memory related question

Posted on 2004-09-10
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Last Modified: 2010-03-31
Dear Java experts

I was wondering... in my code... to display a variable to the console i use the following like 1000+ times:

System.out.println("" + varName);

and

System.out.println("" + varName + " " + varName2);



My questions are related to the "" and " ".

1. In the examples above... does Java consider "" and " " as Strings? i mean... does it allocate (forgive my C example here) sizeof(String) + (numberOfCharsInString * 2 bytes per chars)?

2. Since there are more than 1000 of each in the code... does Java allocate memory for only one " " and ""? or does Java allocate 1000+ " " and ""?

3. Should i do this instead:

private final static String strEmptyString = "";
private final static String strSingleSpace = " ";

System.out.println(strEmptyString  + varName + strSingleSpace  + varName2);

4. Out of curiosity... in Java... can we do: "This is a String".length( );


So thanks in advance to everyone who will take time to clarify this!!

   -Mike

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Question by:oroussea
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CEHJ earned 125 total points
ID: 12028502
1. Probably not. Since these concatenations are done by StringBuffer internally, they will probably get appended as characters to the StringBuffer
2. No 'memory' as such is allocated (although of course memory is allocated for the StringBuffer) as an append happens (see 1.)
3. It's a good idea, as it makes the code more readable, although it won't affect the code footprint as far as memory/execution time is concerned. The Java convention is to capitalize constants.
4. Yes
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by:CEHJ
ID: 12028996
8-)
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