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Imitating % for ints

Posted on 2004-09-13
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Last Modified: 2012-05-05
Hi,

I need to imitate the '%' operator that C offers.
But I also need it to work with floats.
The floats isn't the problem.
What I need it the code that imitates '%' (for negative number too, of course).

Thanks in advance.
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Question by:slavikn
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8 Comments
 
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Expert Comment

by:Sjef Bosman
ID: 12043191
How far did you get yourself? Converting a number to a string isn't too difficult.
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Author Comment

by:slavikn
ID: 12043207
strings? hmm....

while (a >= b)
   a -= b;

but this doesn't work if a and b are negative.
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Accepted Solution

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Sjef Bosman earned 25 total points
ID: 12043260
Ahem :-$ sorry! I thought you meant the % in printf... Never mind...

a%b = a-(int)(a/b)*b

where \ is the integer divide operator. Try if it works for negative numbers.
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Author Comment

by:slavikn
ID: 12043509
> Try if it works for negative numbers.

Yes, it does. Thanks!
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Author Comment

by:slavikn
ID: 12045120
heh   :-D
'fmod' from 'math.h' does exactly the same  :-))
'man pages' say it uses same formula  :-))
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Expert Comment

by:Sjef Bosman
ID: 12045371
They didn't get it from me ;-)  Nor did I do a man fmod, but maybe I will...
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Author Comment

by:slavikn
ID: 12045445
Heh ;-)   I wrote this to say two things:
1) your formula is correct.
2) I could use a ready-made function instead.
:-)))
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Expert Comment

by:Sjef Bosman
ID: 12045663
Better to use fmod, since converting to int will not work for numbers that go beyond integer precision. Probably fmod is then defined as a-floor(a/b)*b. Or so.

Sjef :)
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