Solved

very simple file upload script for multiple files

Posted on 2004-09-17
9
86,385 Views
Last Modified: 2011-08-18
I need an upload script that will upload multiple files at once.  I need to set the file names to be the same everytime.  So it renames the files after uploading.  I need to upload 5-10 files and have them automatically named 1.gif through 10.gif.   I have a couple of scripts that do this fine for one file at a time but I need to do multiple for a slide show.

Thanks-

Heres what I use now.  If I could some how use a meta refresh after submitting.  

Thanks-

<?php

$site_name = $_SERVER['HTTP_HOST'];
$url_dir = "http://".$_SERVER['HTTP_HOST'].dirname($_SERVER['PHP_SELF']);
$url_this =  "http://".$_SERVER['HTTP_HOST'].$_SERVER['PHP_SELF'];

$upload_dir = "../images/";
$upload_url = "http://####";
$message ="";

//create upload_files directory if not exist
//If it does not work, create on your own and change permission.
if (!is_dir("images")) {
      die ("upload_files directory doesn't exist");
}

if ($_FILES['userfile']) {
      $message = do_upload($upload_dir, $upload_url);
}
else {
      $message = "Invalid File Specified. Ignore if you havent clicked upload yet";
}

print $message;

function do_upload($upload_dir, $upload_url) {

      $temp_name = $_FILES['userfile']['tmp_name'];
      $file_name = '1.gif';
      $file_type = $_FILES['userfile']['type'];
      $file_size = $_FILES['userfile']['size'];
      $result    = $_FILES['userfile']['error'];
      $file_url  = $upload_url.$file_name;
      $file_path = $upload_dir.$file_name;

      //File Name Check
    if ( $file_name =="") {
          $message = "Invalid File Name Specified";
          return $message;
    }
    //File Size Check
    else if ( $file_size > 500000) {
        $message = "The file size is over 500K.";
        return $message;
    }
    //File Type Check
    else if ( $file_type == "text/plain" ) {
        $message = "Sorry, You cannot upload any script file" ;
        return $message;
    }

    $result  =  move_uploaded_file($temp_name, $file_path);
    $message = ($result)?"File url <a href=$file_url>$file_url</a><br><img src=$file_url height=\"210\" width=\"210\">" :
                "Somthing is wrong with uploading a file.";

    return $message;
}
?>
<style type="text/css">
<!--
.style1 {
      font-family: Verdana, Arial, Helvetica, sans-serif;
      font-weight: bold;
}
.style2 {font-family: Verdana, Arial, Helvetica, sans-serif}
-->
</style>

<title>Slideshow Upload Page</title><form name="upload" id="upload" ENCTYPE="multipart/form-data" method="post">
  <span class="style1">Upload Slideshow Image<br>
  </span>  
  <input type="file" id="userfile" name="userfile"><br>
  <input type="submit" name="upload" value="Upload">
</form>
<p class="style2">Click Browse to choose the slideshow file (1.gif) on your computer or office network.</p>
<p class="style2">Click Upload</p>
<p class="style2">The image displayed will be in the slideshow on the front page of lulushoponline </p>
<p class="style2"><a href="collage_upload.php">Change Collage Picture</a></p>
<p class="style2"><a href="slideshow_upload.php">Change Slideshow Image</a></p>
<p><span class="style2"><a href="featured_upload.php">Change Featured Items</a></span> </p>
0
Comment
Question by:livegirllove
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9 Comments
 
LVL 48

Assisted Solution

by:hernst42
hernst42 earned 175 total points
ID: 12090629
You can try this modified version of the script:

<?php
if ($_FILES['userfile']) {
    //to see the structure that generates PHP for uploaded files with an name ending with[] uncomment the following line:
    echo '<pre>'; var_dump($_FILES); echo '</pre>';
    $num = 0;
    foreach($_FILES['userfile']['size'] as $id => $size) {
        if ($size == 0) {
            //no or empty file, skip it
            continue;
        }
        $message .= do_upload($id, $upload_dir, $upload_url);
    }
    ++$num;
}

function do_upload($id, $upload_dir, $upload_url) {
    static $counter = 1;

    $temp_name = $_FILES['userfile'][$id]['tmp_name'];
    $file_type = $_FILES['userfile'][$id]['type'];
    $file_size = $_FILES['userfile'][$id]['size'];
    $result    = $_FILES['userfile'][$id]['error'];
    $file_name = $counter . '.gif';
    $file_url  = $upload_url.$file_name;
    $file_path = $upload_dir.$file_name;

    //File Name Check
    if ( $file_name =="") {
        $message = "Invalid File Name Specified for filei $id.";
        return $message;
    }
    //File Size Check
    else if ( $file_size > 500000) {
        $message = "The file size is over 500K for file $id.";
        return $message;
    }
    //File Type Check
    else if ( $file_type == "text/plain" ) {
        $message = "Sorry, You cannot upload any script file" ;
        return $message;
    }

    if (file_exists($file_path)) unlink($file_path);
    $result  =  move_uploaded_file($temp_name, $file_path);
    $message = ($result)?"File url <a href=$file_url>$file_url</a><br><img src=$file_url height=\"210\" widt
h=\"210\">" :
        "Somthing is wrong with uploading a file.";
    ++$counter;
    return $message;
}

?>
.....
<form name="uplVoad" id="upload" ENCTYPE="multipart/form-data" method="post">
<span class="style1">Upload Slideshow Image<br>
</span>
<?php for ($i = 0; $i< 10; ++$i) { ?>File <?=$i?>:
<input type="file" class="userfile" name="userfile[]"><br>
<?php } ?>
<input type="submit" name="upload" value="Upload">
</form>

So the mostimportant thing to know is how the structure of uploaded files will look like if in the form the name is eneded with []
The files will be name from 1 to 10. If a user skips one field for files inbetween the sequence will not ge broken. This is done by the static variable $counter in do_upload as do up_load is only. If one of those files have failed it will be overwritten by the next file.
0
 
LVL 6

Accepted Solution

by:
peyox earned 325 total points
ID: 12090672
Below is a script with basic error handling:
- renames files: 1.gif ... n.gif   n - number of the last file
- checks if file exists
- checks mime format
- checks file size
- it handles up to 10 uploads
- displays upload summary (status of each upload + total number of uploaded files)

Enjoy :-)


<?
      // (C) 2004 Piotr Szwajkowski
      
      // In PHP versions earlier than 4.1.0, $HTTP_POST_FILES should be used instead
      // of $_FILES.

   $form = TRUE;
      $upload_path = "c:\\apache\\htdocs\\test\\";

      $fname = 1;

      for ($i=0;$i<10;$i++)
      {
            list($problem, $error) = upload_file ($upload_path, $fname.".gif", $i);
            if (!$problem)
            {
                  $fname++;
            }
            else
                  echo $i.": ".$error."<br>";
      }
      
      echo "<br>";
      echo --$fname." file(s) uploaded";

      
         
      if ($form)
      {
      ?>
          <form enctype="multipart/form-data" action="<?php echo $SELF_PHP; ?>" method="POST">
          <input type="hidden" name="MAX_FILE_SIZE" value="300000">
          0: <input class="file" type="file" name="file[0]"><br>
          1: <input class="file" type="file" name="file[1]"><br>
          2: <input class="file" type="file" name="file[2]"><br>
          3: <input class="file" type="file" name="file[3]"><br>
          4: <input class="file" type="file" name="file[4]"><br>
          5: <input class="file" type="file" name="file[5]"><br>
          6: <input class="file" type="file" name="file[6]"><br>
          7: <input class="file" type="file" name="file[7]"><br>
          8: <input class="file" type="file" name="file[8]"><br>
          9: <input class="file" type="file" name="file[9]"><br>
          <input type="submit" value="Submit Images">
          </form>
      <?
      }
     
     
      function upload_file ($upload_path, $fname, $fileid)
      {    
            $problem = TRUE;
            
            switch ($_FILES['file']['error'][$fileid])
            {
                case UPLOAD_ERR_FORM_SIZE:
                     $error = "The uploaded file exceeds the 85kb";
                     break;
                case UPLOAD_ERR_NO_FILE:
                     $error = "No file was uploaded";
                     break;
                default:
                     $error = "";
            }
            
            
            //$fname = $_FILES['file']['name'][$fileid];
            $dest = $upload_path.$fname;
            $tmpfile = $_FILES['file']['tmp_name'][$fileid];
            
            if ($tmpfile)
            {
                $info = getimagesize($tmpfile);
              $ftype = $info['mime'];
            
                if ($ftype != "image/gif" && $ftype != "image/jpeg")
                {
                     $error = "File type not supported";
                     $problem = TRUE;
                }
                else
                {
                     if (file_exists($dest))
                     {
                          $error = "File already exists. (".$dest.")";
                          $problem = TRUE;
                     }                    
                     else
                     {
                          copy ($tmpfile,$dest);                    
                          $problem = FALSE;
                     }
                }
            }
      
            return array($problem, $error);
      }    
?>
0
 
LVL 48

Expert Comment

by:hernst42
ID: 12090851
Can you just explain why the other solution fits better for you than mine?
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LVL 1

Author Comment

by:livegirllove
ID: 12090869
Cut and pasted and it worked.  Doesnt fit any better than that.

Although I thought I split the points 325/175 because your answer was informative and worked with the script I was already familiar with.  

Must be tired.  Ill post a comment in community to have it reopened.
0
 
LVL 2

Expert Comment

by:SabreCEO
ID: 13292606
I saw this was one of the top 10 viewed answers, but it took me over an hour to figure somethin out here. So i know this is closed, but so no one else gets confused, The above was wrong:
 $_FILES['userfile'][$id]['type'];
$_FILES['userfile'][$id]['size'];
$_FILES['userfile'][$id]['error'];

is all wrong, so i am correcting it all of those and the others should be

$_FILES['userfile']['type'][$id];
$_FILES['userfile']['size'][$id];
$_FILES['userfile']['error'][$id];
0
 
LVL 1

Author Comment

by:livegirllove
ID: 13292619
hnmm.
ok, i seem to remember it working, but ill have to check through my files.  I cant remember what I used this on....
0
 

Expert Comment

by:mbigrad
ID: 13360520
Hello,

The below script has been causing me problems for quite some time. All it does is upload the filename in to the database. I need it to upload an image into the images directory on our website. Please help.

$sqlQuery = "SELECT * FROM motorcycles WHERE id = '$this->_id'";
$sqlServer->execQuery($sqlQuery);
$data = $sqlServer->getDataSetArray();

$this->_product_image_1 = $data["image_name_1"];
$this->_product_image_2 = $data["image_name_2"];
$this->_product_image_3 = $data["image_name_3"];
$this->_product_image_4 = $data["image_name_4"];
$this->_product_thumbnail = $data["thumbnail"];
             
             

$this->_product_image_dir = "http://www.ourwebsite.com/images" . "/";

$filedir = $GLOBALS["base_imagedir"];
$file_name = "thumb_" . $_FILES['new_thumb']['name'];
 if($_FILES['new_thumb']['name'] != '')
 {
     @unlink($filedir . $file_name);
     $copy = copy($_FILES['new_thumb']['tmp_name'],$filedir . $file_name);
     if($copy){
          echo "$file_name | uploaded successfuly!<br>";
          $real_path = realpath($uploads);
          echo $real_path;
              }else{
         echo "$file_name | could not be uploaded!<br>";
         }      
        $this->_product_thumbnail = $file_name;
 }
Thanks,
mbigrad
0
 
LVL 1

Author Comment

by:livegirllove
ID: 13360711
0

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