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GetLine() Question

I am using get line to store a string:

this is an example program:

#include <iostream>
#include <string>
#include <iomanip>

int main()
{
string strName;

cout << "Enter Name: ";
getline (cin, strName);

return 0;
}

the problem is that when I use get line, you have to hit enter twice. What will happen is, I will hit enter it will move to the next line, but I have to hit enter again for input to terminate.

Why is it doing this?

-Brian

Mysidia

That's rather unusual.. which compiler version/OS environment?

BrianGEFF719

ASKER

Visual C++ 6.0

BrianGEFF719

ASKER

VC++ 6, Windows XP SP2

ASKER CERTIFIED SOLUTION

efn

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itsmeandnobodyelse

On a WinXP VC 6.0 environment happens the same. It is because of that sequence in <string> include file:

for (; ; _C = _I.rdbuf()->snextc())
if (_Tr::eq_int_type(_Tr::eof(), _C))
{_St |= ios_base::eofbit;
break; }
else if (_Tr::eq((_E)_C, _D))
{_Chg = true;
_I.rdbuf()->snextc();
break; }
else if (_X.max_size() <= _X.size())
{_St |= ios_base::failbit;
break; }
else
_X += _Tr::to_char_type(_C), _Chg = true;

The first 'else if' truely finds out that the terminating character was entered *but* calls again _I.rdbuf()->snextc(); So you have to hit <Enter> again. I don't know if that is a bug or how to overcome that strange behavior.

Regards, Alex

SOLUTION

Mysidia

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itsmeandnobodyelse

@efn

thanks, for the answer. I am going to modify STL header file. Or should i rewrite std::string? ;-)

Regards, Alex

teratoma

Have you tried cin.getline?

Mysidia

If you want to resort to changing your own code, then you could try the simpler C stdio library
if you like...

#include <iostream>
#include <string>
#include <iomanip>
#include <cstdio>

int main()
{
string strName;
char buf[512];

printf ("Enter name:");

if ( fgets(buf, sizeof(buf), stdin) ) {
strName = string(buf);
} else {
fprintf(stderr, "Error: unable to read name\n");
return 1;
}

return 0;
}