?
Solved

Select distinct (only one column - and not the first one)

Posted on 2004-09-20
7
Medium Priority
?
250 Views
Last Modified: 2012-06-27
I have the following query:

SELECT "MOT-" & [Moteng_Inventory]![sku] AS sku, IIf(IsNull(DLookUp("[sku]","Moteng Errors","[sku] = '" & [Moteng_Inventory]![sku] & "'")),[Moteng_Inventory]![UPC], DLookUp("[ASIN]","Moteng Errors","[sku] = '" & [Moteng_Inventory]![sku] & "'")) AS [standard-product-id], IIf(IsNull(DLookUp("[SKU]","Moteng Errors","[sku] = '" & [Moteng_Inventory]![sku] & "'")),"UPC","ASIN") AS [product-id-type], Moteng_Inventory.title, Moteng_Template.Brand, Moteng_Inventory.brand, Moteng_Template.ManufacturerPartNumber, Moteng_Template.BulletPoint1, Moteng_Template.BulletPoint2, Moteng_Template.BulletPoint3, Moteng_Template.BulletPoint4, Moteng_Template.BulletPoint5, Moteng_Template.ProductDescription, Moteng_Template.Prop65, Moteng_Template.LegalDisclaimer, Moteng_Template.Memorabilia, Moteng_Template.Autographed, Moteng_Template.ItemType, Moteng_Template.UsedFor1, Moteng_Template.UsedFor2, Moteng_Template.UsedFor3, Moteng_Template.UsedFor4, Moteng_Template.UsedFor5, Moteng_Template.TargetAudience1, Moteng_Template.TargetAudience2, Moteng_Template.TargetAudience3, Moteng_Template.OtherItemAttributes1, Moteng_Template.OtherItemAttributes2, Moteng_Template.OtherItemAttributes3, Moteng_Template.OtherItemAttributes4, Moteng_Template.OtherItemAttributes5, Moteng_Template.SubjectContent1, Moteng_Template.SubjectContent2, Moteng_Template.SubjectContent3, Moteng_Template.SubjectContent4, Moteng_Template.SubjectContent5, Moteng_Template.SearchTerm1, Moteng_Template.SearchTerm2, Moteng_Template.SearchTerm3, Moteng_Template.SearchTerm4, Moteng_Template.SearchTerm5, Moteng_Template.PlatinumKeyword1, Moteng_Template.PlatinumKeyword2, Moteng_Template.PlatinumKeyword3, Moteng_Template.PlatinumKeyword4, Moteng_Template.PlatinumKeyword5, Moteng_Template.MainImageURL, Moteng_Template.SwatchImageURL, Moteng_Template.PackageLengthUnitOfMeasure, Moteng_Template.PackageLength, Moteng_Template.PackageWidth, Moteng_Template.PackageHeight, Moteng_Template.PackageWeightUnitOfMeasure, IIf(Format([Moteng_Inventory]![misc1],'.00')<1,"1.00",Format([Moteng_Inventory]![misc1],'.00')) AS Expr1, Moteng_Template.AgeGenderCategory, Moteng_Template.BikeRimSize, Moteng_Template.Color, Moteng_Template.Curvature, Moteng_Template.DivingHoodThickness, Moteng_Template.Flavor, Moteng_Template.GolfFlex, Moteng_Template.GolfLoft, Moteng_Template.GripSize, Moteng_Template.Hand, Moteng_Template.HeadSize, Moteng_Template.Length, Moteng_Template.LengthUnitOfMeasurement, Moteng_Template.LineCapacity, Moteng_Template.LineWeight, Moteng_Template.Material, Moteng_Template.Packaging, Moteng_Template.PackageQuantity, Moteng_Template.ShaftMaterial, Moteng_Template.ShaftType, Moteng_Template.Size, Moteng_Template.Weight, Moteng_Template.WeightUnitOfMeasurement, Moteng_Template.WeightSupported, Moteng_Template.Parentage, Moteng_Template.ParentSKU, Moteng_Template.RelationshipType, Moteng_Template.VariationTheme, Moteng_Template.ProductTaxCode, Moteng_Template.LaunchDate, Moteng_Template.MAP, IIf([Moteng_QTY]![cost]<10,Format([Moteng_QTY]![cost]/0.87*1.15+4,'.00'),Format([Moteng_QTY]![cost]/0.87*1.15+1,'.00')) AS price, Moteng_Template.SalesPrice, Moteng_Template.SaleStartDate, Moteng_Template.SaleEndDate, Moteng_Template.ConditionType, IIf([Moteng_QTY]![qty]<6,0,[Moteng_QTY]![qty]) AS qty, Moteng_Template.[leadtime-to-ship], Moteng_Template.IsGiftMessageAvailable, Moteng_Template.IsGiftWrapAvailable, Moteng_Template.UpdateDelete, Moteng_Template.Field96, Moteng_Template.Field97, Moteng_Template.Field98, Moteng_Template.Field99, Moteng_Template.Field100, Moteng_Template.Field101, Moteng_Template.Field102, Moteng_Template.Field103, Moteng_Template.Field104, Moteng_Template.Field105, Moteng_Template.Field106, Moteng_Template.Field107, Moteng_Template.Field108, Moteng_Template.Field109, Moteng_Template.Field110, Moteng_Template.Field111, Moteng_Template.Field112, Moteng_Template.Field113, Moteng_Template.Field114, Moteng_Template.Field115, Moteng_Template.Field116, Moteng_Template.Field117, Moteng_Template.Field118, Moteng_Template.Field119, Moteng_Template.Field120, Moteng_Template.Field121, Moteng_Template.Field122, Moteng_Template.Field123, Moteng_Template.Field124, Moteng_Template.Field125, Moteng_Template.Field126, Moteng_Template.Field127, Moteng_Template.Field128, Moteng_Template.Field129, Moteng_Template.Field130, Moteng_Template.Field131, Moteng_Template.Field132, Moteng_Template.Field133, Moteng_Template.Field134, Moteng_Template.Field135, Moteng_Template.Field136, Moteng_Template.Field137, Moteng_Template.Field138
FROM Moteng_Template, Moteng_Eliminate_Bad_UPCs INNER JOIN (Moteng_Inventory INNER JOIN Moteng_QTY ON Moteng_Inventory.sku = Moteng_QTY.sku) ON Moteng_Eliminate_Bad_UPCs.upc = Moteng_Inventory.upc
WHERE (((IIf([Moteng_QTY]![cost]<10,Format([Moteng_QTY]![cost]/0.87*1.15+4,'.00'),Format([Moteng_QTY]![cost]/0.87*1.15+1,'.00')))<>0));

I can't figure out how to select ONLY DISTINCT RECORDS FOR THE STANDARD-PRODUCT-ID FIELD.  Simply adding "distinct" after select won't work because the data in the previous field is different...your help is greatly appreciated.
0
Comment
Question by:jimday1982
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
  • 2
7 Comments
 
LVL 2

Expert Comment

by:wblakely
ID: 12102152
If the data in the previous field is different, then by definition the record is distinct.  The uniqueness of each record returned by your query is determined by the values of every column.
0
 

Author Comment

by:jimday1982
ID: 12102181
That makes sense and I understand that, but my problem (and I know this is out of the ordinary) is that I need to make sure that field (UPC), and only that field, has no duplicates - is this possible?
0
 
LVL 2

Expert Comment

by:wblakely
ID: 12102267
If it does have duplicates what would you do with them? flag them? exclude them from the query result?

To do either, you could run a summary query ("UPCSumary") with a count of UPC ("CountOfUPC") per [standard-product-id] field and link the summary query on [standard-product-id] to your query above.  Then, exclude or flag (whichever you choose) where UPCSummary.CountOfUPC > 1
0
 

Author Comment

by:jimday1982
ID: 12102341
That sounds like an idea - can you provide info on creating a summary query?
0
 
LVL 2

Accepted Solution

by:
wblakely earned 500 total points
ID: 12102738
Here's a sample summary using your data as I understand it.

SELECT IIf(IsNull(Errors!sku),Inventory!UPC,Errors!ASIN) AS [standard-product-id], Count(Inventory.upc) AS CountOfUPC
FROM Moteng_Inventory AS Inventory LEFT JOIN [Moteng Errors] AS Errors ON Inventory.sku = Errors.sku
GROUP BY IIf(IsNull(Errors!sku),Inventory!UPC,Errors!ASIN);

Just shorten the SQL, I've used alias names for your tables (e.g. "Moteng_Inventory AS Inventory").
0

Featured Post

Free Tool: IP Lookup

Get more info about an IP address or domain name, such as organization, abuse contacts and geolocation.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Phishing attempts can come in all forms, shapes and sizes. No matter how familiar you think you are with them, always remember to take extra precaution when opening an email with attachments or links.
This article shows how to get a list of available printers for display in a drop-down list, and then to use the selected printer to print an Access report or a Word document filled with Access data, using different syntax as needed for working with …
Add bar graphs to Access queries using Unicode block characters. Graphs appear on every record in the color you want. Give life to numbers. Hopes this gives you ideas on visualizing your data in new ways ~ Create a calculated field in a query: …
Visualize your data even better in Access queries. Given a date and a value, this lesson shows how to compare that value with the previous value, calculate the difference, and display a circle if the value is the same, an up triangle if it increased…
Suggested Courses

765 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question