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Solved

open a browser window using java

Posted on 2004-09-20
5
1,300 Views
Last Modified: 2006-11-17
Hi,
what can i use to allow the jbutton to open a browser window when i click it?

i used:
==
getAppletContext().showDocument(new java.net.URL("http://www.singnet.com"),"_blank");
==
But there was an error:
==
symbol  : method getAppletContext ()
location: class websms.b1
                     getAppletContext().showDocument(new java.net.URL("http://www.singnet.com"),"_blank");
                               ^
==

How do i solve it?
Thanks
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Comment
Question by:TPoly
5 Comments
 
LVL 3

Expert Comment

by:nesnemis
ID: 12109219
0
 
LVL 6

Accepted Solution

by:
CodingExperts earned 250 total points
ID: 12109297
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LVL 12

Expert Comment

by:Giant2
ID: 12109432
import the netscape.javascript package

JSObject win = JSObject.getWindow(this);            
String args[] = {html, title};
win.call("show", args);

in the HTML you must have:
<script>
  function show(html, title) {
        window.open(html)
    }
</script>
and when you call the applet in the html you must have:
MAYSCRIPT
inserted.

Hope this help you.
Bye, Giant.
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LVL 5

Expert Comment

by:Naeemg
ID: 12109515
hey use the following code to open any default webbrowser.

call the static method in ur button control action event.
BrowserControl.displayURL("www.urwebsite.com");
or
BrowserControl.displayURL("MyHelp/index.html");



//-- save this source as BrowserControl.java


/**
 * <p>Title: Open Browser</p>
 * <p>Description: </p>
 * <p>Copyright: Copyright (c) 2003-2004</p>
 * <p>Company: </p>
 * @author Naeem Shehzad
 * @version Z.0.0.1
 */

import java.io.IOException;

/**
* A simple, static class to display a URL in the system browser.


*
* Under Unix, the system browser is hard-coded to be 'netscape'.
* Netscape must be in your PATH for this to work.  This has been
* tested with the following platforms: AIX, HP-UX and Solaris.


*
* Under Windows, this will bring up the default browser under windows,
* usually either Netscape or Microsoft IE.  The default browser is
* determined by the OS.  This has been tested under Windows 95/98/NT.


*
* Examples:


*
BrowserControl.displayURL("http://www.Mywebsite.com")
*
BrowserControl.displayURL("file://c:\\docs\\index.html")
*
BrowserContorl.displayURL("file:///user/index.html");
*

* Note - you must include the url type -- either "http://" or
* "file://".
*/
public class BrowserControl
{
    /**
     * Display a file in the system browser.  If you want to display a
     * file, you must include the absolute path name.
     *
     * @param url the file's url (the url must start with either "http://"
or
     * "file://").
     */
    public static void displayURL(String url)
    {
        boolean windows = isWindowsPlatform();
        String cmd = null;
        try
        {
            if (windows)
            {
                // cmd = 'rundll32 url.dll,FileProtocolHandler http://...'
                cmd = WIN_PATH + " " + WIN_FLAG + " " + url;
                Process p = Runtime.getRuntime().exec(cmd);
            }
            else
            {
                // Under Unix, Netscape has to be running for the "-remote"
                // command to work.  So, we try sending the command and
                // check for an exit value.  If the exit command is 0,
                // it worked, otherwise we need to start the browser.
                // cmd = 'netscape -remote openURL(http://www.Mywebsite.com)'
                cmd = UNIX_PATH + " " + UNIX_FLAG + "(" + url + ")";
                Process p = Runtime.getRuntime().exec(cmd);
                try
                {
                    // wait for exit code -- if it's 0, command worked,
                    // otherwise we need to start the browser up.
                    int exitCode = p.waitFor();
                    if (exitCode != 0)
                    {
                        // Command failed, start up the browser
                        // cmd = 'netscape http://www.Mywebsite.com'
                        cmd = UNIX_PATH + " "  + url;
                        p = Runtime.getRuntime().exec(cmd);
                    }
                }
                catch(InterruptedException x)
                {
                    System.err.println("Error bringing up browser, cmd='" +
                                       cmd + "'");
                    System.err.println("Caught: " + x);
                }
            }
        }
        catch(IOException x)
        {
            // couldn't exec browser
            System.err.println("Could not invoke browser, command=" + cmd);
            System.err.println("Caught: " + x);
        }
    }
    /**
     * Try to determine whether this application is running under Windows
     * or some other platform by examing the "os.name" property.
     *
     * @return true if this application is running under a Windows OS
     */
    public static boolean isWindowsPlatform()
    {
        String os = System.getProperty("os.name");
        if ( os != null && os.startsWith(WIN_ID))
            return true;
        else
            return false;

    }
    /**
     * Simple example.
     */
    //public static void main(String[] args)
    //{
    //    displayURL("http://www.Mywebsite.com");
    //}
    // Used to identify the windows platform.
    private static final String WIN_ID = "Windows";
    // The default system browser under windows.
    private static final String WIN_PATH = "rundll32";
    // The flag to display a url.
    private static final String WIN_FLAG = "url.dll,FileProtocolHandler";
    // The default browser under unix.
    private static final String UNIX_PATH = "netscape";
    // The flag to display a url.
    private static final String UNIX_FLAG = "-remote openURL";
}
0
 
LVL 12

Expert Comment

by:Giant2
ID: 12109534
I believe using:
>Process p = Runtime.getRuntime().exec(cmd);
there could be some security problem.
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