• C

# Question on checking for the size of a float value

Hello, i'm tyring too check if an float value that someone enters is correct and does not exceed a certain range. Right now I'm trying to use E, where represnts the exponent to a power of 10 and digits represents 1 or more juxtaposed numbers. E can be the lower case, "e". There can be no more than 7 digits in any floating points number excluding the exponent (the decimal point does not count as a digit) Exponents are restriced to range of -38 to 38.

This is what I have right now:

else if(out == 3)
{
int exponent_check = 0;
std::istringstream(Lexeme.substr((Lexeme.length())-2 ,Lexeme.length())) >> exponent_check;
if(((exponent_check >= 38) || (exponent_check <= -38)) &&
((Lexeme.find("e") == ((Lexeme.length())-3)) || (Lexeme.find("E") == ((Lexeme.length())-3)) ||
(Lexeme.find("e") == ((Lexeme.length())-4)) || (Lexeme.find("E") == ((Lexeme.length())-4))) && Lexeme.find(".") != 0)
{
cout << "\n*** ERROR - Float Literal exponent is out of range ( -38 < x < 38 )" << endl;
//                        num_bad_real_constants++;
return 40;
}

I'm trying to check the the length then compare. The number that I am checking is the following:

1.35562127e1

This number should be throwing an error but it doesn't so I need to know what I am doing wrong in the check. Any help with this would be great.
Asked:
###### Who is Participating?

Commented:
addendum to grg99's suggestion:

(0) Get a leading plus or minus, if not found, assume plus.
(1) Get a digit string, if none found, error out.
(2) If there's a dot, get another digit string, if not found, assume .00000
(2a) get a letter, if it's 'E' or 'e':
(2a.a)  get a sign, if not foiund. assume plus.
(2.a.b) get a digit string, if not found, error out.
(2b) if something other than 'E' or 'e' or white chars, error out
0

Software ArchitectCommented:
You can use logaritms. Decimal logarithms tells you the exponent of a floating number.
Make some tests with log() function.
Remember to #include "math.h" header file.

0

Commented:
Hi DancingFighterG,

Perhaps you should have this question in the C++ TA. I can give you a C solution if you want. Alernatively, I can move this question to C++ TA. Since some experts visit both C and C++ TAs, may beyou can wait a while before they see and comment on this.

sunnycoder
0

Commented:
Your exponent is within the range. That's why it is not throwing error.
But, I have got one suggestion for you: Divide your condition statement to different if statements. And don't do the calculation inside a condition statement. Make it as simple as possible. Then it will be easier to debug and understand and errors will be lesser.

-ssnkumar
0

Commented:
Your parsing is a bit loose, what will your code do with the perfectly valid numbers:

1.0e+38

1.0e0000000000038

I'd suggest this approach:

(0) Get a leading plus or minus, if not found, assume plus.
(1) Get a digit string, if none found, error out.
(2) If there's a dot, get another digit string, if not found, assume .00000
(2a) get a letter, if it's 'E' or 'e':
(2a.a)  get a sign, if not foiund. assume plus.
(2.a.b) get a digit string, if not found, error out.

------------------
That's a much more bulletproof way to parse a real constant.

0
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