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Copy from CArray<sVector,sVector> to sVector *ArrayOfVectors

Posted on 2004-09-22
5
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Last Modified: 2010-04-01
Hi,
I have an sVector struct:

typedef t_Vector
{
        double Xcoord,
        double Ycoord,
        double Zcoord
}
and:


CArray<sVector,sVector>              TempVectorsArray;

sVector                                        *ArrayOfVectors;

I need to copy all the element from TempVectorsArray to ArrayOfVectors, but each time
when i get into the copy  i need to copy the data from the TempVectorsArray into a
different place on the ArrayOfVectors,for example:

for(int base_index =0 ; base_index<100; base_index++)
{
     // I need to change this line to the correct form - copy from TempVectorsArray to    
     // ArrayOfVectors[base_index]
     ArrayOfVectors[base_index] = TempVectorsArray;   //now it's error of course
}


Thanks a lot:-)
0
Comment
Question by:dani333
  • 3
5 Comments
 

Author Comment

by:dani333
ID: 12127957
the correct struct is of course :

typedef t_Vector
{
        double Xcoord,
        double Ycoord,
        double Zcoord
}sVector;

sorry for the mistake.
0
 
LVL 22

Accepted Solution

by:
NovaDenizen earned 120 total points
ID: 12128146
Something more like this?

int base_index;
...calc base_index here...
int len = TempVectorsArray.length();
int i;
for(i = 0; i < len; i++) {
    ArrayOfVectors[base_index + i] = TempVectorsArray[i];
}

This copies all elements from TempVectorsArray into a subrange of ArrayOfVectors starting at index base_index.  Make sure that ArrayOfVectors is allocated to be big enough to contain all elements of TempVectorsArray.

0
 

Author Comment

by:dani333
ID: 12128287
yes,but do you have another way without looping all the elements in the array?
with pointers , address or something like that?
0
 

Author Comment

by:dani333
ID: 12128380
Maybe memcpy or ather way....
0
 
LVL 9

Expert Comment

by:jhshukla
ID: 12129238
i would not suggest memcpy unless you are sure that sVectors are laid out in contiguous chunk of memory.
0

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