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Solved

vb.net count characters then add a symbol

Posted on 2004-09-24
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361 Views
Last Modified: 2010-08-05
I am using visual basic and I want to know how I can count so many characters and then add a certain symbol

example that I have is:


L20Tom  Brady   12340golf

It needs to be when the code sees the line that starts with L to
make the line look lke this

L:20:Tom:Brady:12340:Golf

Now the line data will never be the same but it will have the same fixed length. The L will be the identifier to signal to do the above,

So
where 20 is would be 2 characters
Tom = 4 five characters
Brady = 10 characters
12340 = 5 chars
Golf= 4 chars

so lets say the next line would be

L40JimmyBrad    123  base

it would do this to the line

L:40:Jimmy:Brad:123:base

striping out the empty spaces.

Is this hard to do????


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Question by:hogan9111
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7 Comments
 
LVL 44

Expert Comment

by:Arthur_Wood
ID: 12143548
do I understand you correctly that whent the FIRST CHARACTER is a 'L' the line will ALWAYS be laid out as

1 Character
2 DIGITS
5 Characters (may have trailing blanks)
10 Characters (may have trailing blanks)
5 Digits
4 characters

Is that correct?

AW
0
 

Author Comment

by:hogan9111
ID: 12143603
yes the L will never change

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LVL 44

Expert Comment

by:Arthur_Wood
ID: 12143721
and are the other character counts ALWAYS the same

2 characters ('20' in your example) followed by
5 Characters ('Tom  ' or 'Jimmy' in you examples) foloowed by
10 Characters ('Brady     ' or 'Brad      ' in your examples) followed by
5 Characters ('12340' in your example) followed by
4 characteres ('golf' or 'base' in your examples)

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Accepted Solution

by:
Arthur_Wood earned 50 total points
ID: 12143837
If that is the case, then use can use the SubString Method of the String Object, like this:

Dim strTest As String = "L20Tom  Brady     12340golf"
Dim str(5) As String
Dim StrResult As String

str(0) = strTest.Substring(0, 1)
str(1) = strTest.Substring(1, 2)
str(2) = strTest.Substring(3, 5).Trim
str(3) = strTest.Substring(8, 10).Trim
str(4) = strTest.Substring(18, 5)
str(5) = strTest.Substring(23, 1).ToUpper & strTest.Substring(24, 3)

For i As Integer = 0 To 5
    StrResult = StrResult & str(i) & ":"
Next
    StrResult = StrResult.Substring(0, StrResult.Length - 1)


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Expert Comment

by:Shahankit
ID: 12143988
Dim mainLine as string = "L40JimmyBrad    123  base "

Dim temp As String
Dim temp1 As String
Dim temp2 As String
Dim temp3 As String
Dim temp4 As String
Dim temp5 As String

temp = mainLine.Substring(0, 1)
temp1 = mainLine.Substring(2, 4)
temp2 = mainLine.Substring(5, 10)
temp3 = mainLine.Substring(11, 21)
temp4 = mainLine.Substring(22, 27)
temp5 = mainLine.Substring(28, 32)


Dim position1 As Int16 = temp1.IndexOf(" ")
Dim position2 As Int16 = temp2.IndexOf(" ")
Dim position3 As Int16 = temp3.IndexOf(" ")
Dim position4 As Int16 = temp4.IndexOf(" ")
Dim position5 As Int16 = temp5.IndexOf(" ")

If position1> 0 Then
temp1 = temp1.substring(0,position1)
End If
If position2> 0 Then
temp2 = temp2.substring(0,position2)
End If
If position3> 0 Then
temp3 = temp3.substring(0,position3)
End If
If position4> 0 Then
temp4 = temp4.substring(0,position4)
End If
If position5> 0 Then
temp5 = temp5.substring(0,position5)
End If

Dim resultline as string = temp + ":" + temp1 + ":" + temp2 + ":" + temp3 + ":" + temp4 + ":" + temp5


It might not be the best way to solve this problem... but still this will give you resulting string as you want

Best of luck
Ankit
0
 

Author Comment

by:hogan9111
ID: 12144643
one question though: what is this line actually doing??

 StrResult = StrResult.Substring(0, StrResult.Length - 1)
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LVL 44

Expert Comment

by:Arthur_Wood
ID: 12144953
in the loop, I append a ":" after each substring, so this last statement drops the ":" which would have appeared after the LAST block.  It takes the Substring the starts at the first character and extends to the next to last character (Length - 1)

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