addActionListener ....

Hi Experts,

    I have a question about the following code :

  at line 00, does "this" refer to a PlayGame object or the mineButton[i] ?
  so .... must an "addActionListener" work with an actionPerfomed() method ? thanks !
-------------------------

public PlayGame(){
      System.out.print(ROW_NUM + "  " + COL_NUM) ;
      JPanel minePanel = new JPanel() ;
      minePanel.setLayout(new GridLayout(ROW_NUM,COL_NUM)) ;
      for(int i=0 ; i < ROW_NUM*COL_NUM; i++){ mineButton[i] = new Mine(i) ;
                                  mineButton[i].addActionListener(this);   // line 00
                                  minePanel.add(mineButton[i]) ;
      }
LVL 1
meow00Asked:
Who is Participating?

Improve company productivity with a Business Account.Sign Up

x
 
OBCTConnect With a Mentor Commented:
Another way would be to have an anonymous inner class. This way wouldn't necessarily be any easier or harder; however it’s just another option.

I would personally write a method to return your actionListener like so...

private ActionListener getActionListener()
{
    return new ActionListener()
    {
        public void actionPerformed(ActionEvent e)
        {
            // process actions here
        }
    };
}

This way you would have full access to all private members and methods within your class and remove the need for constructing an instance of a separate class.

At the end of the day, there’s heaps of ways you can do this, so just pick your favourite ;-)
0
 
OBCTCommented:
'this' refers to the PlayGame object.
So when calling addActionListener(this), your basically saying that the current ActionListener is implemented in the PlayGame object.
Therefore you'll need to make sure you do implement ActionListener for everything to work ok.
0
 
zzynxSoftware engineerCommented:
this always refers to the current instance of the class it is in, in this case the PlayGame class.
So you add an ActionListener to the mineButton[i].
And that ActionListener is an instance of PlayGame.
To be able to do that, your PlayGame class must implement the ActionListener interface.
That's rather easy: it should implement the actionPerformed function:


     public class PlayGame implements ActionListener {

         
          public void actionPerformed(ActionEvent evt) {
          }


     }
0
Get your problem seen by more experts

Be seen. Boost your question’s priority for more expert views and faster solutions

 
zzynxConnect With a Mentor Software engineerCommented:
You can of course use a new class for the ActionListener:

public class MyActionListener implements ActionListener {
    public MyActionListener() {
    }

    public void actionPerformed(ActionEvent evt) {
       // Do your stuff
    }
}

that way you can write:

public class PlayGame {

   private MyActionListener myActionListener = new MyActionListener();


   ...
   mineButton[i].addActionListener( myActionListener );   // line 00
   ...
}
0
 
zzynxSoftware engineerCommented:
Thanks
0
 
OBCTCommented:
:-)
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.