32bit address generation using command parsing

Hi ,I am very new to PERL.And,I need to write a program to generate a 32 bit number for the below input parameters.I will appreciate your help.

Write a Perl program to generate an number Addr(32-bit address) for the given
input parameters.
Input Arguments--> BL ( Burst Length).
Input Arguments--> DW ( Data Bus Width).

The output file format is described below.
Output file ---> Addr(32-bit hex).

Assumptions:
Lets assume that the BL = 8 and DW = 64(fixed for now).

So the perl program should take BL and DW as inputs and generate
a address sequence like below.

Addr  = { Bank, Row, Col, Byte}

Bank, Row, Col, Byte are local to the perl pogram.The final Addr is packed with these
local variables.The idea is to play with the local variables and generate the final Addr.

Bank ---> ranges from {0...7} decimal numbers(3 bits in binary)
Row  ---> ranges from {0....16383} decimal numbers(14 bits in binary).
Col  ---> ranges from {0....1023} decimal numbers(10 bits in binary).
Byte ---> ranges from {1.....8}   decimal numbers(3 bits in binary).


Lets clamp Bank and Row to be always 0 for now.
Since the Bank and Row are always 0, so the higher order bits(14 to 31) are always 0.
The only remaining are Col and Byte.

Generate the below sequence using the col and Byte.

(a) Byte  ----Start at decimal 1 and increment upto 8(8 inclusive).
    Col   ----Initially for the first time Keep the col to 0.
    So the final Hex addr looks like 0x0000001
                                     0x0000002
                                     0x0000003.......0x00000008
                                         

(b) Now Increment the col by 1 and repeat (a).
   
(c) Do it upto col value  8.

In essence start from col value 0 and increment byte from 1 to 8 values.
Increment col value by 1 and repeat the byte increment starting from 1 to 8 values again.
Stop when col value 8.Effectively you should have 64 hex addresses in
the output file.

Write the output file in hex.