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how to terminate printing an array of ints

Posted on 2004-09-29
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Last Modified: 2010-03-31
Hello,

I have this array of 0s and 1s. Originally the array is initialized to all 1s, and then using this method:

public static int bitSwap(int[] swapArray)
{
      
for (k=0; k < swapArray.length; k++)
{

if (swapArray[k] == 0)
{
swapArray[k] = 1;
}
else
{

swapArray[k] = 0;
j=k;
break;
}

}

It switches 1s to 0s and 0s to 1s, but once a 1 has been flipped to 0, the code breaks. This method returns the index at which the 0 was flipped, which is what i need it to do. The user passes an integer value, which determines the size of the array that is passed to this method. My question is this:

I need to print the return statement of this method in a loop of some kind. I know that when the array passed contains ALL 0s in it's indices, then it needs to stop, but I can't figure out how to make it do that.
Help would be appreciated.

-NeedlessKane
0
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Question by:NeedlessKane
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10 Comments
 
LVL 92

Accepted Solution

by:
objects earned 25 total points
ID: 12184916
heres a method to print the array contents.:

public static void print(int[] a)
{
   for (int i=0; i<a.length; i++) System.out.print(a[i]+" ");
   System.out.println();
}
0
 
LVL 92

Expert Comment

by:objects
ID: 12184933
use something like the following in your loop to display the processing:

print(a);
int result = bitSwap(a);
System.out.println(result);
0
 

Author Comment

by:NeedlessKane
ID: 12185003
Yeah, but I need to keep printing the values of bitSwap until the array that is passed is full of 0s, how can I make it check to see when the array is all 0s?
0
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LVL 92

Expert Comment

by:objects
ID: 12185047
you'll need to check the array contents after each call.

boolean allzero = false;
for (int i=0; allzeroes && i<a.length; i++) if (a[i]==1) allzeroes = false;
0
 

Author Comment

by:NeedlessKane
ID: 12185192
Hrmm, still working w/ it. How exactly does that && statement work in the for loop? Like what's the logic behind that.
0
 
LVL 92

Expert Comment

by:objects
ID: 12185213
&& is an and, so the expression is only true if both the expressions are true
0
 

Author Comment

by:NeedlessKane
ID: 12185400
This is what i'm trying and it's not working:

int d;
boolean allzero = true;
for (d=0; allzero && d<diskMove.length; d++)
bitSwap(diskMove);
if (diskMove[d]==1)
allzero = false;
else{
System.out.println(diskMove[d]);
     }


0
 

Author Comment

by:NeedlessKane
ID: 12185846
Still not working, i've tried alot of things, agh.

All i need to do is run that bitSwap() in a loop and stop it each time....then after it stops, check the current array to see if all the values are == 0, if they aren't == to 0, run bitSwap again, and keep doing that over and over, but i'm at a loss.
0
 
LVL 3

Assisted Solution

by:CI-Ia0s
CI-Ia0s earned 25 total points
ID: 12186209
I'd add "allzero = true;" to the top of the else statement:

int d;
boolean allzero = true;
for (d=0; allzero && d<diskMove.length; d++)
bitSwap(diskMove);
if (diskMove[d]==1)
allzero = false;
else{
allzero = true;
System.out.println(diskMove[d]);
}
0
 
LVL 92

Expert Comment

by:objects
ID: 12186854
>  if they aren't == to 0, run bitSwap again, and keep doing that over and over, but i'm at a loss

your call to bitSwap needs to be outside your loop.

> I'd add "allzero = true;" to the top of the else statement

Not really necessary, as allzero is already true.

0

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