Solved

File upload error

Posted on 2004-09-30
8
3,358 Views
Last Modified: 2012-06-22
Hi all,

I have a problem,

I have adjusted a file that used the "SoftArtisans Fileup" upload script to change it to use the "aspupload" script.

I get the following error......Please help !!! :( what am I doing wrong?

ERROR------

Microsoft VBScript runtime error '800a01b6'

Object doesn't support this property or method: 'upl.path'

/admin/publication.asp, line 120

CODE----

LINE 18     If id="add2" then
LINE 19      set upl=Server.CreateObject("Persits.Upload")
LINE 20      upl.path=(server.mapPath("/articles"))
etc      if not (upl.IsEmpty) then
            upl.save
      End If
      response.write("<h6>:: Add Article ::</h6>")
      Set rs = Server.CreateObject("ADODB.Recordset")
      SQL = "SELECT * FROM Articles where id is  null"



ORIGINAL CODE-----
If id="add2" then
      set upl=Server.CreateObject("SoftArtisans.FileUp")
      upl.path=("d:\web\articles")
      if not (upl.IsEmpty) then
            upl.save
      End If
      response.write("<h6>:: Add Article ::</h6>")
      Set rs = Server.CreateObject("ADODB.Recordset")
      SQL = "SELECT * FROM Articles where id is  null"
0
Comment
Question by:MaximusMeridus
  • 4
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8 Comments
 
LVL 11

Expert Comment

by:coopzz
ID: 12189306
Well the new object your wanting to use is different to the other one.. so naturally they don't share the same interface.

ie: it dont' support this property or method  (upl.path...)

you have to rewrite the upload saving to the new object.

heres some links to get you going
http://support.persits.com/upload/demo1.asp 
http://www.aspupload.com/object_upload.html
http://www.aspupload.com/ObjectReference.htm
0
 
LVL 1

Author Comment

by:MaximusMeridus
ID: 12189355
Is it possible that you adjust the code relevantly as I am not that experienced.

Many thanks

Max
0
 
LVL 11

Accepted Solution

by:
coopzz earned 500 total points
ID: 12189454
don't know never used the object but looking at the demo in the first link it'd be something like this.

If id="add2" then
     set upl=Server.CreateObject("Persits.Upload.1")
     upl.OverwriteFiles = False
     'On Error Resume Next
     upl.SetMaxSize 1048576      ' Limit files to 1MB
     dim Count: Count = upl.Save(server.mapPath("/articles"))
   
     response.write("<h6>:: Add Article ::</h6>")
     Set rs = Server.CreateObject("ADODB.Recordset")
     SQL = "SELECT * FROM Articles where id is  null"

if you can't get it to work try the demo and download it, get it going and play with it and you'll get it.
It can't be that hard.. just make sure you have permission to upload to the directory that your uploading to.
0
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LVL 1

Author Comment

by:MaximusMeridus
ID: 12189672
Hi I tried the following and go this message....the end is LINE 150


ERROR ----
Microsoft OLE DB Provider for ODBC Drivers error '80004005'

[Microsoft][ODBC Microsoft Access Driver] Field 'Articles.fname' cannot be a zero-length string.

/admin/publication.asp, line 150

CODE---

If id="add2" then
     set upl=Server.CreateObject("Persits.Upload.1")
     upl.OverwriteFiles = False
     'On Error Resume Next
     upl.SetMaxSize 1048576     ' Limit files to 1MB
     dim Count: Count = upl.Save(server.mapPath("/articles"))
   
     response.write("<h6>:: Add Article ::</h6>")
     Set rs = Server.CreateObject("ADODB.Recordset")
     SQL = "SELECT * FROM Articles where id is  null"


      Dim bigContent
      'for i=1 to upl.Form("content").Count
      '      bigcontent = content & upl.Form("content")(i)
      'Next
      bigContent = upl.Form("content")
      bigContent=sortit(bigContent)
      pdate = upl.Form("pub_date")
      StrDay =  Mid(pdate, 1,2)
      StrMonth= Mid(pdate,4,2)
      StrYear=  Mid(pdate,7,2 )
      'pdate = StrMonth & "/" &  StrDay & "/" & StrYear
      rs.open sql,dbconn,adOpenForwardOnly,adLockOptimistic
      rs.addnew
      rs.Fields("pub_date").value =  pdate
      rs.fields("headline").value = CStr(upl.Form("headline"))
      rs.fields("content").value = bigContent
      rs.fields("publication_Id").value = CStr(upl.Form("publication"))
      'Response.Write("Fname: " & upl.form("fname"))
      
      rs.Fields("fname").value = Cstr(upl.form("fname"))
                rs.update
0
 
LVL 11

Expert Comment

by:coopzz
ID: 12189801
try replacing this
rs.Fields("fname").value = Cstr(upl.form("fname"))

with
rs.Fields("fname").value = Cstr(upl.form(0).value) 'or
rs.Fields("fname").value = Cstr(upl.form(("fname").value)

I take it "fname" is the name of the input form object
0
 
LVL 1

Author Comment

by:MaximusMeridus
ID: 12190245
Now I get this error...:(

Persits.Upload.1 error '800a0009'

Index out of range.

/admin/publication.asp, line 149
0
 
LVL 11

Expert Comment

by:coopzz
ID: 12190312
whoopa I think maybe this should be
rs.Fields("fname").value = Cstr(upl.form(1).value) 'note the 1 has changed from 0.
0
 
LVL 1

Author Comment

by:MaximusMeridus
ID: 12190914
You're a star!

Excellent!

Max
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