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Finding the percent SQL syntax

Hello,

My last columns are trying to find the percent of items that contain a L or an R, you get the idea. However, the only percent im coming up with is 0, any suggestions?

Thank You

SELECT
      LINNBR As "Number",
      COD As "Code",
      Convert(varchar, DAT, 101) As "Date",
      Left(CAGE, 2) As House,
      DateDiff("d", DAT, VAL) As "Age",
      Sum( Case When NBR <> 0 Then 1 End) As "Total_Count",
      Avg(BW) AS "Weight",
      Avg([BW]/DateDiff("d", DAT, VAL)) As "ADG",
      Avg(BC) As AvgBC,
      Avg(FE) As AvgFe,
      Sum( Case When Stat1 = 'E' Then 1 End) As "Elites",
      Avg( Case When Stat1 = 'E' Then (BWT1) End) As "Avg_Weight_E",
      (Sum( Case When Defects1 like '%L%' Then 1 else 0 End)) As "%L",
      100*(Sum( Case When Def like '%T%' Then 1 else 0 End)/Sum( Case When NBR <> 0 Then 1 End)) As "%T",
      100*(Sum( Case When Def like '%K%' Then 1 else 0 End)/Sum( Case When NBR <> 0 Then 1 End)) As "%K",
      100*(Sum( Case When Def like '%R%' Then 1 else 0 End)/Sum( Case When NBR <> 0 Then 1 End)) As "%R",
      100*(Sum( Case When Def like '%V%' Then 1 else 0 End)/Sum( Case When NBR <> 0 Then 1 End)) As "%V",
      100*(Sum( Case When Def like '%D%' Then 1 else 0 End)/Sum( Case When NBR <> 0 Then 1 End)) As "%D",
      100*(Sum( Case When Def like '%S%' Then 1 else 0 End)/Sum( Case When NBR <> 0 Then 1 End)) As "%S"
FROM
      PSBRLEVLP
WHERE
      VAL <> ''
GROUP BY
      LINNBR,
      COD,
      DAT,
      Left(CAGE, 2),
      DateDiff("d", DAT, VAL)

jdlambert1

You probably have some nulls, which sets it all null. Try substituting:

NULLIF(NBR, 0)

for

NBR

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ASKER

NBR is a keyed field that wont allow Null's

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ASKER

sorry, you did mean i probally have null's in the NBR field right?

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BillAn1

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arbert

Possibly SQL Server's implicit conversion on the data type--try this:

100*(Sum( Case When Def like '%T%' Then 1 else 0 End)/Sum( Case When NBR <> 0 Then 1.00 End)) As "%T"

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ASKER

Cast worked great, thank you all for your input