• C

WHats the output of printf(" %u",function)



printf(" %u",fun);

where fun was a function with the void type and more interestingly the function is written without "()" in the above printf statement.

What will be the output and why?
thebeseusAsked:
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hongjunCommented:
it's the address of the function in unsigned integer format.
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hongjunCommented:
everything is associated with an address in memory.
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stefan73Commented:
Hi thebeseus,
functions without () are passed as addresses. fun and &fun are the same.

Cheers!

Stefan
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grg99Commented:
Good question.  

You're going to get some number printed.
Only two things to say about this:

(1)  "fun" without the "()" means the ADDRESS of fun.

(2)  Printing out an address in %u format  is not guarateed to do the right thing.
It will work on computers where an unsigned int happens to be the same size as an address, which includes x86 in real mode, small memory model, or x86 32-bit mode.   Otherwise the number printed is going to be incorrect.

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hongjunCommented:
thebeseus,
    your question is answered. Do you need further assistance?

hongjun
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