Improve company productivity with a Business Account.Sign Up

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 236
  • Last Modified:

java programming

public class FileSync {
  private File outFile;
  private PrintStream outStream;

  public FileSync() throws IOException {
      outFile = new File("c:/orisree/java/ran.txt");
      outStream = new PrintStream(new FileOutputStream(outFile));
  }

  public Object getSyncObject() {
      return outFile;
  }

  public void writeToFile(String text) throws IOException {
      outStream.println(text);
  }
}
**************************************************
public class TestSynch extends Thread {

  public TestSynch() {
  }
  public static void main(String[] args) {
      WriteThread[] threads = new WriteThread[3];
      try {
          for(int i = 0; i < threads.length; i++) {
              threads[i] = new WriteThread();
          }

          for(int i = 0; i < threads.length; i++) {
              threads[i].start();
          }

      }catch(IOException ioe) {
          ioe.printStackTrace(System.err);
      }
  }
}
***************************
public class WriteThread extends Thread {
  private static int threadCount;
  private int threadNum;
  private FileSync fileSync;

  static {
      threadCount = 0;
  }

  public WriteThread() throws IOException {
      threadNum = ++threadCount;
      fileSync = new FileSync();
  }

  public void run() {
      Object syncObject = fileSync.getSyncObject();
      synchronized(syncObject) {
          for(int i = 0; i < 100; i++) {
              try {
                  fileSync.writeToFile("Printing from thread " + threadNum + " line " + i);
              }catch(IOException ioe) {
                  ioe.printStackTrace(System.err);
              }
          }
      }
  }
}



From the above 3 classes,when i run TestSynch i get output , for 1 to 21, i get threadnum=1
then from 22 to 54, i get threadnum=3 ,after that until 99 i get threadnum=1,
How does synchObject allow thread 3 to come in between thread 1.pls give me the answer at the earliest.
Urgent..


0
sraveend
Asked:
sraveend
  • 7
  • 2
  • 2
  • +2
2 Solutions
 
objectsCommented:
>       synchronized(syncObject) {

the synchronized code block can only be run by one thread at a time.
other will be blocked until the thread completes the block.
0
 
sraveendAuthor Commented:
U r correct only one thread runs,then how i got the thread 3 in between thread1 in my program
0
Upgrade your Question Security!

Your question, your audience. Choose who sees your identity—and your question—with question security.

 
objectsCommented:
thats just how the threads get scheduled, try running it a few times and see.
0
 
arataniCommented:
Basically, every thread takes some time on the CPU. Then, after its time is taken the next thread gets its chance. So, from 1-21 was threads 1 time running on the CPU. Then, you got thread 3  to run on the CPU. And so on, the scheduling is fully random.

Is that what you are looking for, or do you want to know how to block Thread 1 to execute?

AJ
0
 
objectsCommented:
> And so on, the scheduling is fully random.

not sure that its exactly random
0
 
gen718Commented:
It's not random. Higher priority threads get more processor time than lower priority threads. Other than that, the exact behavior (thread selection) is dependent on the VM and the operating system.

A running thread remains running until it blocks, yields or is forcibly swapped off the processor by the thread scheduler.
0
 
objectsCommented:
yes that sounds better, the link above provides some more details.
0
 
sraveendAuthor Commented:
I just don't find any difference in the output with Synchronization code or without synchronization code.
Is it due to ,blocking only the file and not the printstream object.I just want to know the role of synchronization......
0
 
arataniCommented:
The role of synchronization is to protect data from being accessed when it shouldn't be. For example, if you have two threads accessing the same data then you might not want both the threads to change the data at the same time. So, you would synchronize the method or the section of the code that changes the data to prevent it from being accessed simultaneously.

http://www.janeg.ca/scjp/threads/synchronized.html

will show you the purpose behind synchronized.

In your code,

saying synchronized (syncObject) {


}

gets a lock on the syncObject at the start of the code. So, now no other threads can modify or work with syncObject. And it is released at the end of the closing brace (}).

To find out more about using the synchronized keyword, read this,

http://www.jguru.com/faq/view.jsp?EID=42569

Also, raed about the article on what it means to get a lock?

The reason there is no difference in the synchronized code and non-synchronized is since they are not changing the object in any way. If you look at the first link I showed you, you will see the purpose of synchronization.

AJ
0
 
objectsCommented:
> .I just want to know the role of synchronization......

It is to ensure only one threads executes a block of code at the same time.
0
 
babuno5Commented:
Hello,
I think this might just help u
try setting the Priority of the threads set the maximum priority which is to be completed first

Thread.MAX_PRIORITY
Thread.MIN_PRIORITY
Thread.NORM_PRIORITY
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

Featured Post

Free Tool: Site Down Detector

Helpful to verify reports of your own downtime, or to double check a downed website you are trying to access.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

  • 7
  • 2
  • 2
  • +2
Tackle projects and never again get stuck behind a technical roadblock.
Join Now