[2 days left] What’s wrong with your cloud strategy? Learn why multicloud solutions matter with Nimble Storage.Register Now

x
?
Solved

java.lang.NullPointerException

Posted on 2004-10-04
5
Medium Priority
?
286 Views
Last Modified: 2010-03-31
This is problem that I am facing currently.

I want to read a file only if the file name contains a certain string value.But, if the file name doesnt contain that string, it is throwing java.lang.NullPointerException.Please have a look at the code as I have pointed where the error occurs.Also, let me know if you have any further questions.Thanks for your help!

public static void unzipAndGetEntries(String zipfilename , Date fromDDt , Date toDDt, String profileName){
      
            
            
             System.out.println(" Zip File Name : " + zipfilename);
            
          try{
                 Date fromDDDt = fromDDt;
                 Date toDDDt = toDDt;
                 String transactionName = "";
                           String InbOrOut = rco.getDirection(); // inbound or outbound
                           InputStream f = null;
                                     ZipFile myzipfile = new ZipFile(zipfilename);
                  
                  for (int y = 0;y < wantedTransactionList.size();y++){
        transactionName = ((ProfileObject)wantedTransactionList.elementAt(y)).getName();              
             
             for (Enumeration e = myzipfile.entries(); e.hasMoreElements();){
                ZipEntry ze = ((ZipEntry)e.nextElement());
                String fileNm =  ze.getName();
      System.out.println(" File Name : " + fileNm);
               
                // for example file name abc.zip/outbound/processed/123456_52532.txt
               // it throws null pointer exception if it doesnt find "outbound" in the file name.
                if ((fileNm.indexOf(InbOrOut)!=-1) && (fileNm.indexOf("processed")!=-1))
      if (ze.getSize()>0){
                System.out.println(" File Name : " + fileNm);
                f = myzipfile.getInputStream(ze);
                        
                    readTheFileContent(f,fileNm,profileName,transactionName,fromDDDt,toDDDt);
                   
                }
               
                ze = null;
                fileNm = null;
               
               
              }
             
    }        
           fromDDDt = null;
           toDDDt = null;
           f.close();
           myzipfile.close();  
         
             
          } catch (IOException e){ System.out.println("Error while unzipping the files : " );
            e.printStackTrace();}        
              
          
      }  



0
Comment
Question by:g46905
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
  • 2
5 Comments
 
LVL 92

Expert Comment

by:objects
ID: 12222078
whats the stack trace?
0
 

Author Comment

by:g46905
ID: 12222146
Here it is. Please let me know if you want me to post the entire code.
java.lang.NullPointerException
      at ReportStats.unzipAndGetEntries(ReportStats.java:596)
      at ReportStats.getLogsFromArchives(ReportStats.java:531)
      at ReportStats.main(ReportStats.java(Compiled Code))

Thanks,
0
 
LVL 92

Expert Comment

by:objects
ID: 12222184
which is line 596
0
 

Author Comment

by:g46905
ID: 12222223
Here it is

           f.close(); // line 596

This is present in the code mentioned above.

Thanks,
0
 
LVL 92

Accepted Solution

by:
objects earned 200 total points
ID: 12222237
remove that statement, and instead close after calling readTheFileContent:

                  f = myzipfile.getInputStream(ze);            
                  readTheFileContent(f,fileNm,profileName,transactionName,fromDDDt,toDDDt);
                  f.close();
                 
                }
               
                ze = null;
                fileNm = null;
               
               
              }
             
    }        
           fromDDDt = null;
           toDDDt = null;
           myzipfile.close();  
0

Featured Post

On Demand Webinar - Networking for the Cloud Era

This webinar discusses:
-Common barriers companies experience when moving to the cloud
-How SD-WAN changes the way we look at networks
-Best practices customers should employ moving forward with cloud migration
-What happens behind the scenes of SteelConnect’s one-click button

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

INTRODUCTION Working with files is a moderately common task in Java.  For most projects hard coding the file names, using parameters in configuration files, or using command-line arguments is sufficient.   However, when your application has vi…
Java had always been an easily readable and understandable language.  Some relatively recent changes in the language seem to be changing this pretty fast, and anyone that had not seen any Java code for the last 5 years will possibly have issues unde…
Viewers learn how to read error messages and identify possible mistakes that could cause hours of frustration. Coding is as much about debugging your code as it is about writing it. Define Error Message: Line Numbers: Type of Error: Break Down…
Viewers will learn about the different types of variables in Java and how to declare them. Decide the type of variable desired: Put the keyword corresponding to the type of variable in front of the variable name: Use the equal sign to assign a v…
Suggested Courses

649 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question