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double numbers

Posted on 2004-10-05
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Last Modified: 2008-03-06
Hi dear experts;

I have two double numbers like following
double A= 0.6;
double B=0.5;

when i try to subtract B from A like following
system.Out.print(A-B);
it gives me  0.0999999998  but i want the result to be  0.10 or 0.1
how can i do this ?  i try ceil floor and round methods of Math class but they didint work
it is an error of java ?
because  when i try to 0.8-06= 0.200000000000004  i want to see result like 0.2
Sincerely,



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Question by:elmakarge
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3 Comments
 
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armoghan earned 250 total points
ID: 12225282
see this for rounding the double
http://www.rgagnon.com/javadetails/java-0016.html
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by:armoghan
ID: 12225310
public static final double roundDouble(double d, int places)
{        
return Math.round(d * Math.pow(10, (double) places)) / Math.pow(10,            (double) places);    
}
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Expert Comment

by:cjjclifford
ID: 12225325
This is because of the nature of floating point numbers, and arithmetic... the .999999998 result is not an error....
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