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error in string handling

Posted on 2004-10-05
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Last Modified: 2012-06-27

can somebody tell me what's wrong with this ?
_____________________________________________________
string x1,filename;

      char t[]="C:\\";
      char ext[]=".txt";

      cout << "Enter x1";
      cin >>x1;

      filename=strcat(t,x1.c_str());
      filename=strcat(filename.c_str(),ext);

      cout << endl<< "Filename= " <<filename;
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Question by:anshuma
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9 Comments
 
LVL 45

Expert Comment

by:Kent Olsen
ID: 12225980

What happens when you compile / run it?

0
 

Author Comment

by:anshuma
ID: 12225999
filename=strcat(filename.c_str(),ext);

it say this line has error in it

 error C2664: 'strcat' : cannot convert parameter 1 from 'const char *' to 'char *'
        Conversion loses qualifiers
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LVL 45

Expert Comment

by:Kent Olsen
ID: 12226101

Your usage of the variable 'filename' invokes a conflict.  On one hand, you're passing it to strcat () as a 'const char *', but you also try to use it as the receiving field which is a 'char *'.

Use another variable for the first parameter or the receiving field.

Kent
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Author Comment

by:anshuma
ID: 12226161
couldn't get it to work, could you show me.
0
 
LVL 45

Expert Comment

by:Kent Olsen
ID: 12226273


string x1,filename, temp;

     char t[]="C:\\";
     char ext[]=".txt";

     cout << "Enter x1";
     cin >>x1;

     temp=strcat(t,x1.c_str());
     filename=strcat(temp.c_str(),ext);

     cout << endl<< "Filename= " <<filename;

0
 

Author Comment

by:anshuma
ID: 12226359
Its not working, I use VC++
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LVL 8

Accepted Solution

by:
mnashadka earned 75 total points
ID: 12226523
What I think you want here is:
string x1;
char t[]="C:\\";
char ext[]=".txt";

cout << "Enter x1";
cin >>x1;

x1 = t + x1 + ext; // Concatenate the strings.  Note: this only works with strings.  Don't use it with char *'s or char []'s.

cout << endl<< "Filename= " <<filename;
0
 
LVL 8

Expert Comment

by:mnashadka
ID: 12226545
Sorry, if you have another string named filename, you should change:
x1 = t + x1 + ext;
To:
filename = t + x1 + ext;

Same concept, just different variable.  Hope this helps.
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LVL 45

Assisted Solution

by:Kent Olsen
Kent Olsen earned 50 total points
ID: 12226651

Good Catch, mnashadka.  I've got C code on the brain and obviously wrapped them around each other......

Kent
0

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