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batch file question

Posted on 2004-10-05
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hi!

I have this batch file, and can someone tell what does these lines do?

@echo off
java extractHeader g:\temp mri for header ext

thanks,
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Question by:dkim18
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Assisted Solution

by:CEHJ
CEHJ earned 80 total points
ID: 12231704
1. don't echo output
2. run java class 'extractHeader' passing remainder of line as parameters to the java program
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Author Comment

by:dkim18
ID: 12231804

what does "g:\temp"  do on second line?

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by:CEHJ
ID: 12231908
Possibly just a directory parameter to the java program
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LVL 92

Expert Comment

by:objects
ID: 12232326
> what does "g:\temp"  do on second line?

it is passed as an argument to the java application.
the application will use that value (accessible from args passed to main)
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Expert Comment

by:CEHJ
ID: 12232343
>>it is passed as an argument to the java application ...

Already mentioned
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Expert Comment

by:objects
ID: 12232385
I'm providinding clarification and more information to help dkim18, why do you have a problem with that?

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Author Comment

by:dkim18
ID: 12233307
Let's not fight too much over points...

I understand it is passed as arguement. I was was wondering there were any relationships among "g:\temp", 'mri', 'for' ,  'header',  'ext', since there were spaces among those. However, I didn't any particular code that treat them as second, or thrid arguement.

Sorry if my question wasn't clear. I thought "g:\temp", does anything special to other args.
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Expert Comment

by:objects
ID: 12233340
> Let's not fight too much over points...

funnily enuf the points don't bother me :)

not sure why cehj has a problem with me trying to help.

> I was was wondering there were any relationships among "g:\temp", 'mri', 'for' ,  'header',  'ext', since there were spaces among those.

they are just seperate args, it depends on how the app deals with them:

args[0]="g:\temp"
args[1]="mri"
args[2]="for"
args[3]="header"
args[4]="ext"
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Author Comment

by:dkim18
ID: 12233437
Now, I found the following code in the main. (I am reading someone else's code that was written a few years ago  and there are a few same files..)

      public static void main(String[] args) throws Exception
      {

      while (true){
            String mappedDrive;

            try
            {      
                  if (args[0] != null)
                        mappedDrive = args[0];
                  else
                        mappedDrive = "E";
            }
            catch (Exception e)
            {
                  mappedDrive = "E";
            }

            UIManager.setLookAndFeel(new MetalLookAndFeel());
            JFileChooser chooser = new JFileChooser();

            if (runOnce == false)
                  startDir = mappedDrive + ":" + System.getProperty("file.separator") + "scans\\Scans_for_header_ext";

            File directory = new File(startDir);

            chooser.setCurrentDirectory(directory);
            chooser.setFileSelectionMode(JFileChooser.FILES_AND_DIRECTORIES);
            int returnVal = chooser.showOpenDialog(null);
            if (returnVal == JFileChooser.APPROVE_OPTION)
            {
                  if (runOnce == false)
                        startDir = getStartPath(chooser.getSelectedFile().getAbsolutePath());
            
                  String fileOutPath = System.getProperty("user.home") + System.getProperty("file.separator") +
                        "Desktop" + System.getProperty("file.separator") + "001.hdr";

                  File outf = new File(getOutPath(chooser.getSelectedFile().getAbsolutePath()));

                  PrintWriter out = new PrintWriter(new FileWriter(outf));
System.out.println(outf);
System.out.println(chooser.getSelectedFile());
                  DicomFile dicom = new DicomFile(chooser.getSelectedFile());

                  Vector ElementNameVector = dicom.getElementNameVector(); // names of catagories
                  Vector ElementValueVector = dicom.getElementValueVector(); // bunch of large numbers
                  Vector ElementDataStringVector = dicom.getElementDataStringVector(); // data

                  Object[] catagories = ElementNameVector.toArray();
                  Object[] data = ElementDataStringVector.toArray();

                  String finalHeader = "(";
            
                  for (int i = 0; i < ElementNameVector.size(); i++)
                  {
                        finalHeader = finalHeader + "(" + catagories[i].toString() + " " + data[i].toString() + ") ";
                  }
            
                  out.print(finalHeader);
                  out.print(")");
                  out.close();
            
            }
            else
                  System.exit(0);

            if (runOnce == false)
                  runOnce = true;
      }
      }
++++++++++++
what does "scans\\Scans_for_header_ext" do for the following line?

startDir = mappedDrive + ":" + System.getProperty("file.separator") + "scans\\Scans_for_header_ext";

(\\ indicates double back slash)

thanks,
-I increased points since I am asking different question


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LVL 92

Accepted Solution

by:
objects earned 520 total points
ID: 12233462
it creating a string containing a file path to the directory Scans_for_header_ext.
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Author Comment

by:dkim18
ID: 12233696
does "scans\" do anything special?
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LVL 92

Expert Comment

by:objects
ID: 12233970
no, thats just a directory name.

eg. if mappedDrive was "E" then startDir would be:

E:\scans\Scans_for_header_ext
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LVL 92

Assisted Solution

by:objects
objects earned 520 total points
ID: 12233976
> startDir = mappedDrive + ":" + System.getProperty("file.separator") + "scans\\Scans_for_header_ext";

you'd get the same effect with:

startDir = mappedDrive + ":/scans/Scans_for_header_ext";
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Author Comment

by:dkim18
ID: 12234023
thank you so much!
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LVL 92

Expert Comment

by:objects
ID: 12234124
no worries bud :)
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Expert Comment

by:CEHJ
ID: 12235631
8-)
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