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Get Date In XML

I would like to know if there is a way to get the date using xml, or if there is some way to get the date via javascript or something. Because I need to be able to compare the current date to one in the document is the XSL if statement. Any ideas?
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gf3
Asked:
gf3
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1 Solution
 
rdcproCommented:
Using Extension functions it's possible.  This example uses MSXML:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
            xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
            xmlns:map="urn:schemas-rdcpro-com:xslt-map"
            xmlns:msxsl="urn:schemas-microsoft-com:xslt"
            xmlns:dates="urn:rdcpro-com:dates"
            >
      <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
      <msxsl:script language="JScript" implements-prefix="dates">
            <![CDATA[
                  function getDate() {
                        var oDate = new Date();
                        return oDate.getFullYear() + "-" + (oDate.getMonth() + 1) + "-" + oDate.getDate();
                  }
            ]]>
      </msxsl:script>
      <xsl:template match="/">
            <h2>Today's Date</h2>
            <xsl:value-of select="dates:getDate()"/>
      </xsl:template>
</xsl:stylesheet>

However, I think it's much better to set the date as a parameter externally, using the addParameter() method or whatever similar mechanism your processor has.  In MSXML, it would be:

var xslt = new ActiveXObject("Msxml2.XSLTemplate.4.0");
var xslDoc = new ActiveXObject("Msxml2.FreeThreadedDOMDocument.4.0");
var xslProc;
xslDoc.async = false;
xslDoc.resolveExternals = false;
xslDoc.load("sample.xsl");
xslt.stylesheet = xslDoc;
var xmlDoc = new ActiveXObject("Msxml2.DOMDocument.4.0");
xmlDoc.async = false;
xmlDoc.resolveExternals = false;
xmlDoc.load("books.xml");

date = new date();

if (xmlDoc.parseError.errorCode <> 0) {
   var myErr = xmlDoc.parseError;
   alert("You have error " + myErr.reason);
} else {
   xslProc = xslt.createProcessor();
   xslProc.input = xmlDoc;
   xslProc.addParameter("param1", date.toDateString());
   xslProc.transform();
   alert(xslProc.output);
}


Extension functions are a security issue, and in some platforms, code that uses them must run with elevated privileges. But they work.  They are not necessarily portable across platforms.


Regards,
Mike Sharp
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gf3Author Commented:
Sorry I didnt mention this earlier but this application will be linux based. So I don't believe that I have access to MSXML. Is there another way to do this?
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rdcproCommented:
Linux is the operating system...the question is, what XSLT processor are you using?  When you mentioned Javascript, I used MSXML as a generalized example.  Many XSLT processors use extension functions, some of them natively. Even Saxon, which doesn't have a scripting engine, can use java.  Take a look at http://exslt.org for a vast library of extensions.    

Personally, as I said, I would probably use the addParameter approach, as the XSLT can be cross-platform that way, and you avoid a few other pitfalls.  It's probably faster, too.  Consult your XSLT processor documentation on the syntax for this.

Regards,
Mike Sharp
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gf3Author Commented:
Thanks for the help, really sorry about the huge delay. I forgot about and it and i came over it again while cleaning up my inbox. Thanks again for the help!
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