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# string to BigInteger array

Posted on 2004-10-07
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2,160 Views
Last Modified: 2012-06-21
I have a string (contents) wich is a concatation of numbers (129012002150...) and I use every group of 3 to load a BigInteger array with them:

BigInteger[] B_array;
Int i;

i = 0;
for (int x=0; x < contents.length()-3; x+=3)
{
B_array[i] = BigInteger.valueOf(contents.substring(x,x+3)));
i = i +1;
}

and it doesn't work. I want to have in my B_array something like:
129
12
2
150
.
.
0
Question by:edi02
[X]
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18 Comments

LVL 37

Expert Comment

ID: 12248743
BigInteger.valueOf() doesn't take a String
0

LVL 37

Expert Comment

ID: 12248750
Try

B_array[i] = new BigInteger(contents.substring(x,x+3));
0

LVL 37

Expert Comment

ID: 12248827
This works:

String contents = "129012002150";
BigInteger[] B_array = new BigInteger[contents.length()/3];      // <<<<< have to new these ones
int i = 0;
for (int x=0; x <= contents.length()-3; x+=3) {                        // x <= instead of x <
B_array[i] = new BigInteger(contents.substring(x,x+3));
i++;
}
0

LVL 37

Expert Comment

ID: 12248845
Add

for (int  j=0; j<B_array.length; j++)
System.out.println( ((BigInteger)B_array[j]).floatValue());

To check the result
0

Author Comment

ID: 12248864
thanx
0

LVL 37

Expert Comment

ID: 12248961
You're welcome.
Kindly close this Q if you feel like your problem is solved.
0

Author Comment

ID: 12248979
May i ask u one more question ...

How do you transform from Integer to BigInteger?
0

LVL 37

Expert Comment

ID: 12249031
Integer i = new Integer(2000);
BigInteger b = new BigInteger("" + i);
0

LVL 37

Expert Comment

ID: 12249054
Or

BigInteger b = BigInteger.valueOf(i.intValue());
0

Author Comment

ID: 12249171
I tried that and got this error:

C:\Second\second.java:167: int cannot be dereferenced
p_calc[indic] = BigInteger.valueOf(p_found.intValue());
Were i have at the start:

private static BigInteger[] p_calc = new BigInteger[100];
0

Author Comment

ID: 12249195
This worked:

p_calc[indic] = new BigInteger("" + p_found);
0

LVL 37

Expert Comment

ID: 12249330
>> int cannot be dereferenced

if p_found is an int then that should have been
p_calc[indic] = BigInteger.valueOf(p_found);

The one you wrote would work id p_found was an Integer
0

LVL 37

Accepted Solution

zzynx earned 500 total points
ID: 12249510
Still questions/problems?
0

Author Comment

ID: 12249872
Ahh hopefully the last one ... :-)

Trying to convert a String to a Char. I know exactly my Strings are all between 0 and 255. So im sure they will have each of them a Char representation.

0

LVL 37

Expert Comment

ID: 12250089
Do you mean a String that contains from "0" to "255" ?
>> String to Char
You mean Character of char?

String s = "123";
char c = (char) Integer.parseInt(s);
0

LVL 37

Expert Comment

ID: 12250174
Since you posted another Q for that last question, please close this one.
0

LVL 5

Expert Comment

ID: 12250273
can this code help u out.

String myStr = "ThisData";
Char[] myChar = new Char[myStr.getLength()];

for(int i = 0; i < myStr.getLenght(); i++)
myChar[i] = myStr.charAt(i);

Bye
Naeem Shehzad Ghuman
0

LVL 37

Expert Comment

ID: 12250367
Thanks.

(Better accept the real "answer" as answer for the people that read it afterwards)
0

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