Testing in a shell script (maybe some sed issues)
I'm trying to determine if a process is running and I'm having some issues with my script. I'm using the '-z' flag on a test which should return True if the string is not a 0 value. My thinking is that the ps-ef command string (example below) through grep will only return a line if that process is running (that part works). What does not work is the -z test always shows the process as running even if it's not. I thought maybe there was a newline character in there so that's where I started messing with sed (shown below).
if [ -z 'ps -ef | grep "{any process name}" | grep -v "grep" | sed -e "/^ *$/d"' ];then
echo 'Process not running\n'
else
echo 'Process running\n'
fi
Unfortunately there's no flags on the executable that I am actually testing that will return a code if it's running (runs as a daemon) so I thought this was the best way. I'm open to suggestions though. Eventually this will run every 5 minutes and restart the process if it stops.
Thanks in advance for any help.
if [ -z 'ps -ef | grep "{any process name}" | grep -v "grep" | sed -e "/^ *$/d"' ];then
echo 'Process not running\n'
else
echo 'Process running\n'
fi
Unfortunately there's no flags on the executable that I am actually testing that will return a code if it's running (runs as a daemon) so I thought this was the best way. I'm open to suggestions though. Eventually this will run every 5 minutes and restart the process if it stops.
Thanks in advance for any help.
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ASKER
Them pesk backticks again! Works now, thanks for the help.
should say:
RES=`ps -ef | grep 'bash' | grep -v 'grep'`
RES=`ps -ef | grep 'bash' | grep -v 'grep'`
ASKER
That works as well griessh, thanks for the alternative. I had already accepted tfewster's answer before I read yours though.
No problem, he was first :-)
RES=`ps -ef | grep 'bash' | grep -v 'grep'
if [ -z "$RES" ];then
...
fi
which makes it easier to debug :-)