asked on

open a very huge file (48 GB) in C++ or C

I need open a very huge file and until now I could not open it!
So I need help about it. The characteristics of my PC are: 2GB RAM, 2.99 GHz, I am compiling with Visual C++ and OS is Windowd

main()
{

char *path1 = "C:\\Reconstruction\\quad-HIDAC_data\\Test_File.lst";
char buffer[1024];

fstream fin; // object from fstream class

fin.open(path1,ios::binary,ios::in);

if(!fin.is_open())
{
cout << "Fail....";
return 0;
}
else
{

// do somthig

fin.close();
}

}

ASKER CERTIFIED SOLUTION

jkr

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ormale67

ASKER

I will complie this code,

thanks !

Axter

I recommend that you also use MapFile API function in addition to CreateFile API function.

That will speed up your code when reading and writing.

ormale67

ASKER

I already answer this question, and this is the code that could work for open a huge file: This example was found
with the help of Visual C++ 6.0.

/* OPEN.C: This program uses _open to open a file
* named OPEN.C for input and a file named OPEN.OUT
* for output. The files are then closed.
*/

#include <fcntl.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <io.h>
#include <stdio.h>

void main( void )
{
int fh1, fh2;

fh1 = _open( "OPEN.C", _O_RDONLY );
if( fh1 == -1 )
perror( "open failed on input file" );
else
{
printf( "open succeeded on input file\n" );
_close( fh1 );
}

fh2 = _open( "OPEN.OUT", _O_WRONLY | _O_CREAT, _S_IREAD |
_S_IWRITE );
if( fh2 == -1 )
perror( "Open failed on output file" );
else
{
printf( "Open succeeded on output file\n" );
_close( fh2 );
}
}