int main(void)
{
int Deck[52], Counter[13], i, j, m, r, k, FullHouse=0;
double t = clock();

/* ------ Initialize Deck ------ */

for (j=0; j<13; j++) {
Counter[j]=0; }
for (i=0; i<52; i++) {
Deck[i] = i; }

printf("the program is running\nthe first hand with a full house is:\n\n");

/* -------- Shuffle Deck ------- */

for (k=0; k<n; k++) {
for (i=51; i>0; i--) {
Exchange(&Deck[i], &Deck[rand()%(i + 1)]); }}

/* -------- Draw a Hand -------- */

for (m=0; m<5; m++) {
Counter[Deck[m]%13]++; }

/* --- Check for Full House ---- */

for (r=0; r<13; r++) {
if (Counter[r]==3) {
for (j=0; j<13;j++) {
if (Counter[j]==2) {
FullHouse++;
if (FullHouse==1) {
for (i=0; i<5; i++) {
printf("%s of %s\n", CardValue[Deck[i]%13], Suit[Deck[i]/13]); }}}}}}
for (j=0; j<13; j++) {
Counter[j]=0; }
t = clock() - t;
printf("\nthe experimental probability of two cards with the same value is %1f\n", (double)FullHouse/k);
printf("the time taken equals %f seconds\n", t/CLOCKS_PER_SEC);
return 0;
}

void Exchange(int* iPtr, int* jPtr) {
int k = *iPtr;
*iPtr = *jPtr;
*jPtr = k; }

</code>

The output that I am supposed to be getting is:

Three of Hearts
Three of Spades
Two of Spades
Three of Diamonds
Two of Hearts

the experimental probability of a full house is 0.001438
the time taken equals 3.423568 seconds.

The program shuffles the deck a million times and deals one hand. It doesn't report on that one hand unless it is a full house. The odds are that the hand will not be a full house, and so the program will not report its contents.

If you want to evaluate the experimental probability of a getting a full house, it would be helpful to examine more than one hand.

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If you want to evaluate the experimental probability of a getting a full house, it would be helpful to examine more than one hand.